Question

我是SQL的新手，从来没有写过任何复杂的查询，我需要帮助。我有下表 -

    Platform   |   TestSuite  |   TestCase   |   Status    |
    -----------|--------------|--------------|-------------|
    Win 2012   |    TS1       |    TC1       |    PASS     |
    Win 2012   |    TS1       |    TC2       |    PASS     |
    Win 2012   |    TS1       |    TC3       |    FAIL     |
    Win 2012   |    TS1       |    TC4       |    ABORT    |
    Win 2012   |    TS2       |    TC5       |    PASS     |
    Win 2012   |    TS2       |    TC6       |    PASS     |
    Win 2012   |    TS2       |    TC7       |    FAIL     |
    Win 2016   |    TS1       |    TC1       |    PASS     |
    Win 2016   |    TS1       |    TC2       |    PASS     |
    Win 2016   |    TS1       |    TC3       |    FAIL     |
    Win 2016   |    TS1       |    TC4       |    ABORT    |
    Win 2016   |    TS2       |    TC5       |    PASS     |
    Win 2016   |    TS2       |    TC6       |    PASS     |
    Win 2016   |    TS2       |    TC7       |    FAIL     |
    -----------|--------------|--------------|-------------|

我需要编写SQL查询来生成以下结果

    Platform   |   TestSuite  |   PASS   |   FAIL  |   ABORT  | TOTAL | 
    -----------|--------------|----------|---------|----------|-------|
    Win 2012   |    TS1       |    2     |    1    |     1    |  4    |
    Win 2012   |    TS2       |    2     |    1    |     0    |  3    |
    Win 2016   |    TS1       |    2     |    1    |     1    |  4    | 
    Win 2016   |    TS2       |    2     |    1    |     0    |  3    |

Answer 1

您正在寻找conditional aggregation。以下是sum和case的一种方法，适用于大多数数据库（尽管mysql支持简写版本）：

select platform, testsuite, 
    sum(case when status = 'pass' then 1 else 0 end) pass,
    sum(case when status = 'fail' then 1 else 0 end) fail,
    sum(case when status = 'abort' then 1 else 0 end) abort,
    count(*) total
from yourtable
group by platform, testsuite

或者因为您使用的是mysql：

select platform, testsuite, 
    sum(status = 'pass') pass,
    sum(status = 'fail') fail,
    sum(status = 'abort') abort,
    count(*) total
from yourtable
group by platform, testsuite

MySql查询组由多个列和多个计数组合在一起

1 个答案: