Question

<Send>
   <Title>myTitle</Title>
   <User>username</User>
   <Transaction>106100</Transaction>
   <Items>
     <Item ID="12345" Name="myName" Birthday="myBirthday" Address="myAddress"/>
   </Items>
</Send>

如果我有这种XML文档。如何在12345代码中获取ID（ <Item ... /> ）的值？使用VB.Net？

Answer 1

请尝试以下操作：

Imports System.Xml
Imports System.Xml.Linq

Module Module1
    Const FILENAME As String = "c:\temp\test2.xml"
    Sub Main()
        Dim doc As XDocument = XDocument.Load(FILENAME)

        Dim items As List(Of Item) = doc.Descendants("Item").Select(Function(x) New Item() With { _
                                                                        .id = x.Attribute("ID").Value, _
                                                                        .name = x.Attribute("Name").Value, _
                                                                        .birthday = x.Attribute("Birthday").Value, _
                                                                        .address = x.Attribute("Address").Value _
                                                                    }).ToList()

    End Sub

End Module
Public Class Item
    Public id As String
    Public name As String
    Public birthday As String
    Public address As String

End Class

Answer 2

这就是我想要的...

其中itemID包含12345

_strMessage = 
        <Send>
           <Title>myTitle</Title>
           <User>username</User>
           <Transaction>106100</Transaction>
           <Items>
             <Item ID="12345" Name="myName" Birthday="myBirthday" Address="myAddress"/>
           </Items>
        </Send>

    Dim xMessage As XElement = XElement.Parse(_strMessage) 
    Dim items = xMessage.Descendants("Items").FirstOrDefault 
    Dim itemID As String = String.Empty 
    itemID = items.Descendants("Item").FirstOrDefault.Attribute("itemID").Value

如何从XML文档中获取值（VB.NET）

2 个答案: