Question

$test = array
(
    "0" => array
        (
            "isLibrary" => 1,
            "isActive" => 1,
            "title" => "Mytitle1234",
            "nps" => 750000001456,
            "system" => "Remote",
            "system_path" =>"./remote/system/test"
        ),
    "1" => array
        (
            "isLibrary" => 1,
            "isActive" => 1,
            "title" => "Mytitle1234",
            "nps" => 750000001456,
            "system" => "Local",
            "system_path" =>"./local/system/test"
        )
)

这是我的阵列。 PHP中是否有任何预定义的函数，以便我可以得到如下结果。

$test = array
    (
        "0" => array
            (
                "isLibrary" => 1,
                "isActive" => 1,
                "title" => "Mytitle1234",
                "nps" => 750000001456,
                "locations" => array (
                        "Remote" => array (
                             "system" => "Remote",
                             "system_path" =>"./remote/system/test"
                             ),
                        "local" => array (
                             "system" => "Local",
                             "system_path" =>"./local/system/test"
                             )
                  )
             )

我想组合数组，并希望根据系统值制作子数组。

Answer 1

您可以使用array_diff分离所需的部分，然后从这些部分构建新数组。

$remote = array_diff($test[0], $test[1]);
$local = array_diff($test[1], $test[0]);

//what is not "remote", meaning the start of the array
$new[] = array_diff($test[0], $remote); 
// Add remote and local
$new[0]["locations"] =["remote" => $remote, "local" => $local];

Var_dump($new);

https://3v4l.org/KHlu8

编辑：忘记0索引，添加[]和[0]。

如果您不确定远程或本地是否在[0]中，您可以使用此代码。

$temp = array_diff($test[0], $test[1]);
$locations["locations"][$temp["system"]] = $temp; 
$temp = array_diff($test[1], $test[0]);
$locations["locations"][$temp["system"]] = $temp; 


$new[] = array_diff($test[0], $locations["locations"][$test[0]["system"]]);
$new[0] =array_merge($new[0], $locations);

Var_dump($new);

它保存了临时数组中的差异，然后根据位置数组中的内容构建位置数组。

https://3v4l.org/BNQXZ

Answer 2

预定义的功能不会为您创建自定义数组，但这里有如何构建它。

<?php

$old = 
[
    [
        "isLibrary" => 1,
        "isActive" => 1,
        "title" => "Mytitle1234",
        "nps" => 750000001456,
        "system" => "Remote",
        "system_path" =>"./remote/system/test"
    ],
    [
        "isLibrary" => 1,
        "isActive" => 1,
        "title" => "Mytitle1234",
        "nps" => 750000001456,
        "system" => "Local",
        "system_path" =>"./local/system/test"
    ],
];

$new = [
    "isLibrary" => $old[0]['isLibrary'],
    "isActive" => $old[0]['isActive'],
    "title" => $old[0]['title'],
    "nps" => $old[0]['nps'],
    "locations" => [
        "remote" => [
            "system" => $old[0]['system'],
            "system_path" => $old[0]['system_path'],  
        ],  
        "local" => [
            "system" => $old[1]['system'],
            "system_path" => $old[1]['system_path'],  
        ],  
    ],
];


var_dump($new);

哪个输出：

array(5) { 
["isLibrary"]=> int(1) 
["isActive"]=> int(1) 
["title"]=> string(11) "Mytitle1234" 
["nps"]=> int(750000001456) 
["locations"]=> array(2) { 
    ["remote"]=> array(2) { 
        ["system"]=> string(6) "Remote" 
        ["system_path"]=> string(20) "./remote/system/test" 
  } ["local"]=> array(2) { 
        ["system"]=> string(5) "Local" 
        ["system_path"]=> string(19) "./local/system/test" 
    } 
  } 
}

在此处查看https://3v4l.org/rZEF3

Answer 3

$res = [];
foreach ($test as $info) {
    $key = $info["isLibrary"] .  $info["isActive"] . $info["title"] . $info["nps"];
    if (isset($res[$key])) {
        $res[$key]['locations'][$info['system']] = [
            "system" => $info['system'],
            "system_path" => $info["system_path"],
        ];
    } else {
        $res[$key] = [
            "isLibrary" => $info["isLibrary"],
            "isActive" => $info["isActive"],
            "title" => $info["title"],
            "nps" => $info["nps"],
            "locations" => [
                $info['system'] => [
                    "system" => $info['system'],
                    "system_path" => $info["system_path"],
                ],
            ],
        ];
    }
}

$res = array_values($res);
print_r($res);

从多维数组创建子数组

3 个答案: