Question

我的代码：

def saveJSONget(site, code):
        response = requests.get(site)
        json_str = json.dumps(response.json())
        if not response.status_code == code:
            file = open("PATH", 'w')
            file.write(str(response.text) + "\n")

我需要保存文件json所有信息：标头响应和请求，请求有效负载。我不知道使用什么函数，写入文件这个元素。我有第二个问题。

如何改变我的方法？错误：

Error
Traceback (most recent call last):
  File "/usr/lib/python3.6/unittest/case.py", line 59, in testPartExecutor
    yield
  File "/usr/lib/python3.6/unittest/case.py", line 601, in run
    self.setUp()
  File "PATH", line 13, in setUp
    Class.method(site, 210)
  File "PATHy", line 171, in method
    json_str = json.dumps(response.json())
  File "/usr/lib/python3.6/json/__init__.py", line 354, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python3.6/json/decoder.py", line 339, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python3.6/json/decoder.py", line 357, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

谢谢你的帮助

Answer 1

List<SwitchListTiles>

JSON保存到文件get方法

1 个答案: