仅返回数组php中存在的值

Question

我有这个

$array1 = ['apple'];

$array2 = ['apple', 'orange'];

我想检查array1中是否有来自array2的任何值并返回该值。我试过in_array($array1, $array2);它只返回true或false。

Answer 1

您正在寻找array_intersect()

$array1 = ['apple'];;
$array2 = ['apple', 'orange'];
$result = array_intersect($array1, $array2);
print_r($result);

Answer 2

有一个函数(define-generic-mode 'foo-mode ;; name of the mode to create '("#") ;; comments start with '!!' '("for" "if" "else" ) ;; some keywords '(("=" . 'font-lock-operator) ;; '=' is an operator ("+" . 'font-lock-operator) ;; '=' is an operator ("-" . 'font-lock-operator) ;; '=' is an operator ("<-" . 'font-lock-operator) ;; '=' is an operator ("*" . 'font-lock-operator) ;; '=' is an operator ("/" . 'font-lock-operator) ;; '=' is an operator ("," . 'font-lock-builtin) ;; ';' is a built-in (";" . 'font-lock-builtin)) ;; ';' is a built-in '("\\.myext$") ;; files for which to activate this mode '((lambda () (modify-syntax-entry ?' "\""))) ;; other functions to call "A generic mode for myext files" ;; doc string for this mode ) 使用

array_intersect()

  

array_intersect（）比较两个数组的值，并返回匹配

Answer 3

in_array会返回true或false，所以当它为真时你可以将它添加到数组中：

$array1 = ['apple'];
$array2 = ['apple', 'orange', 'apple'];
$result = [];
foreach ($array2 as $a2) {
    if (in_array($a2, $array1)) {
        $result[] = $a2;
    }
}
print_r(array_unique($result));