我最近才开始使用java中的zip文件。到目前为止，似乎所有人都计划好了，但我有最后一个障碍：嵌套拉链。
我正在尝试搜索具有特定扩展名的文件，以便将它们作为文本文件读取。到目前为止，我可以很高兴地读取zip文件中的文件，但我知道拉链内的一些文件嵌套在其他拉链内。
有没有办法从ZipEntry中搜索创建ZipFile对象而无需解压缩文件？
没有代码示例，因为它不直接代码问题。
K.Barad
答案 0 :(得分：1)
ZipInputStream将流包装在解压缩数据的过滤器中。因此，当您发现ZipEntry是嵌套的zip文件时，您需要将您正在使用的流包装在新的ZipInputStream中以转换数据。这可以根据您的需要进行。
答案 1 :(得分：1)
我写了一些代码来从拉链中读取文件，就好像它们是虚拟文件夹一样，欢迎您查看它，并了解它是如何工作的。现在，当你说“没有解压缩”这是不可能的，但我认为你的意思是“没有解压缩到磁盘”。这段代码会对其进行解压缩，但它会在内存中进行，而不是在磁盘上进行。
import java.io.*;
import java.util.Deque;
import java.util.LinkedList;
import java.util.logging.Level;
import java.util.logging.Logger;
import java.util.zip.ZipEntry;
import java.util.zip.ZipException;
import java.util.zip.ZipFile;
import java.util.zip.ZipInputStream;
/**
* Allows read operations to happen transparently on a zip file, as if it were a
* folder. Nested zips are also supported. All operations are read only.
* Operations on a ZipReader with a path in an actual zip are expensive, so it's
* good to keep in mind this when using the reader, you'll have to balance
* between memory usage (caching) or CPU use (re-reading as needed).
*/
public class ZipReader {
/**
* The top level zip file, which represents the actual file on the file system.
*/
private final File topZip;
/**
* The chain of Files that this file represents.
*/
private final Deque<File> chainedPath;
/**
* The actual file object.
*/
private final File file;
/**
* Whether or not we have to dig down into the zip, or if
* we can use trivial file operations.
*/
private final boolean isZipped;
/**
* Creates a new ZipReader object, which can be used to read from a zip
* file, as if the zip files were simple directories. All files are checked
* to see if they are a zip.
*
* <p>{@code new ZipReader(new File("path/to/container.zip/with/nested.zip/file.txt"));}</p>
*
*
* @param file The path to the internal file. This needn't exist, according
* to File, as the zip file won't appear as a directory to other classes.
* This constructor will however throw a FileNotFoundException if it
* determines that the file doesn't exist.
*/
public ZipReader(File file){
chainedPath = new LinkedList<File>();
this.file = file;
//make sure file is absolute
file = file.getAbsoluteFile();
//We need to walk up the parents, putting those files onto the stack which are valid Zips
File f = file;
chainedPath.addFirst(f); //Gotta add the file itself to the path for everything to work
File tempTopZip = null;
while ((f = f.getParentFile()) != null) {
chainedPath.addFirst(f);
try {
//If this works, we'll know we have our top zip file. Everything else will have
//to be in memory, so we'll start with this if we have to dig deeper.
if (tempTopZip == null) {
ZipFile zf = new ZipFile(f);
tempTopZip = f;
}
} catch (ZipException ex) {
//This is fine, it's just not a zip file
} catch (IOException ex) {
Logger.getLogger(ZipReader.class.getName()).log(Level.SEVERE, null, ex);
}
}
//If it's not a zipped file, this will make operations easier to deal with,
//so let's save that information
isZipped = tempTopZip != null;
if(isZipped){
topZip = tempTopZip;
} else {
topZip = file;
}
}
/**
* Returns if this file exists or not. Note this is a non-trivial operation.
*
* @return
*/
public boolean exists(){
if(!topZip.exists()){
return false; //Don't bother trying
}
try{
getInputStream().close();
return true;
} catch(IOException e){
return false;
}
}
/**
* Returns true if this file is read accessible. Note that if the file is a zip,
* the permissions are checked on the topmost zip file.
* @return
*/
public boolean canRead(){
return topZip.canRead();
}
/**
* Returns true if this file has write permissions. Note that if the file is nested
* in a zip, then this will always return false
* @return
*/
public boolean canWrite(){
if(isZipped){
return false;
} else {
return topZip.canWrite();
}
}
/*
* This function recurses down into a zip file, ultimately returning the InputStream for the file,
* or throwing exceptions if it can't be found.
*/
private InputStream getFile(Deque<File> fullChain, String zipName, final ZipInputStream zis) throws FileNotFoundException, IOException {
ZipEntry entry;
InputStream zipReader = new InputStream() {
@Override
public int read() throws IOException {
if (zis.available() > 0) {
return zis.read();
} else {
return -1;
}
}
@Override
public void close() throws IOException {
zis.close();
}
};
boolean isZip = false;
while ((entry = zis.getNextEntry()) != null) {
//This is at least a zip file
isZip = true;
Deque<File> chain = new LinkedList<File>(fullChain);
File chainFile = null;
while ((chainFile = chain.pollFirst()) != null) {
if (chainFile.equals(new File(zipName + File.separator + entry.getName()))) {
//We found it. Now, chainFile is one that is in our tree
//We have to do some further analyzation on it
break;
}
}
if (chainFile == null) {
//It's not in the chain at all, which means we don't care about it at all.
continue;
}
if (chain.isEmpty()) {
//It was the last file in the chain, so no point in looking at it at all.
//If it was a zip or not, it doesn't matter, because this is the file they
//specified, precisely. Read it out, and return it.
return zipReader;
}
//It's a single file, it's in the chain, and the chain isn't finished, so that
//must mean it's a container (or it's being used as one, anyways). Let's attempt to recurse.
ZipInputStream inner = new ZipInputStream(zipReader);
return getFile(fullChain, zipName + File.separator + entry.getName(), inner);
}
//If we get down here, it means either we recursed into not-a-zip file, or
//the file was otherwise not found
if (isZip) {
//if this is the terminal node in the chain, it's due to a file not found.
throw new FileNotFoundException(zipName + " could not be found!");
} else {
//if not, it's due to this not being a zip file
throw new IOException(zipName + " is not a zip file!");
}
}
/**
* Returns a raw input stream for this file. If you just need the string contents,
* it would probably be easer to use getFileContents instead, however, this method
* is necessary for accessing binary files.
* @return An InputStream that will read the specified file
* @throws FileNotFoundException If the file is not found
* @throws IOException If you specify a file that isn't a zip file as if it were a folder
*/
public InputStream getInputStream() throws FileNotFoundException, IOException {
if (!isZipped) {
return new FileInputStream(file);
} else {
return getFile(chainedPath, topZip.getAbsolutePath(), new ZipInputStream(new FileInputStream(topZip)));
}
}
/**
* If the file is a simple text file, this function is your best option. It returns
* the contents of the file as a string.
* @return
* @throws FileNotFoundException If the file is not found
* @throws IOException If you specify a file that isn't a zip file as if it were a folder
*/
public String getFileContents() throws FileNotFoundException, IOException {
if (!isZipped) {
return FileUtility.read(file);
} else {
return getStringFromInputStream(getInputStream());
}
}
/*
* Converts an input stream into a string
*/
private String getStringFromInputStream(InputStream is) throws IOException {
BufferedReader din = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
try {
String line;
while ((line = din.readLine()) != null) {
sb.append(line).append("\n");
}
} catch (IOException ex) {
throw ex;
} finally {
try {
is.close();
} catch (Exception ex) {
}
}
return sb.toString();
}
/**
* Delegates the equals check to the underlying File object.
* @param obj
* @return
*/
@Override
public boolean equals(Object obj) {
if (obj == null) {
return false;
}
if (getClass() != obj.getClass()) {
return false;
}
final ZipReader other = (ZipReader) obj;
return other.file.equals(this.file);
}
/**
* Delegates the hashCode to the underlying File object.
* @return
*/
@Override
public int hashCode() {
return file.hashCode();
}
}
答案 2 :(得分：0)
不确定。您不需要ZipFile。创建从外部文件的ZipEntry读取内容的ZipInputStream。