Question

Frist我很抱歉因为我的Enlgish不好我正在研究Spring Framework，我正在做简单的应用程序使用Spring Boot，Spring Data，Spring MVC ..现在我有错误，但我不知道为什么

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'describe='Education', name_room='Boston', id_status='2' where id_room='1'' at line 1

这是我的代码

房间模型

@Entity
@Table(name ="room")
 public class Room implements Serializable {
 private static final long serialVersionUID = 1L;
 @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "ID_room", nullable = false)
    private String id;


    @Column(name = "name_room", nullable = false)
    private String name;


    @Column(name = "Describe")
    private String describe;

    @Column(name = "ID_status")
    private String status;

    public Room() {
        super();
    }

    public Room(String id, String name, String describe, String status) {
        super();
        this.id = id;
        this.name = name;
        this.describe = describe;
        this.status = status;

    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getDescribe() {
        return describe;
    }

    public void setDescribe(String describe) {
        this.describe = describe;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }

}

RoomController

@GetMapping("/manager/{id}/edit")
public String edit(@PathVariable String id, Model model) {
    model.addAttribute("room", romService.findOne(id));
    return "roomForm";
}

@PostMapping("/manager/save")
public String save(@Valid Room room, BindingResult result, RedirectAttributes redirect) {
    if (result.hasErrors()) {
        return "roomform";
    }
    romService.save(room);
    redirect.addFlashAttribute("success", "Saved user successfully!");
    return "redirect:/manager";
}

代码是可行的，但我有关于SQL的错误..我不知道为什么..高兴的帮助我

Hibernate: update room set describe=?, name_room=?, id_status=? where id_room=?
2018-06-08 09:41:12.881  WARN 9308 --- [io-8080-exec-10] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 1064, SQLState: 42000
2018-06-08 09:41:12.882 ERROR 9308 --- [io-8080-exec-10] o.h.engine.jdbc.spi.SqlExceptionHelper   : You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'describe='Education', name_room='Boston', id_status='2' where id_room='1'' at line 1

Answer 1

这是因为'describe'是Mysql中的关键字，不应该使用。为此字段指定其他名称。

或者，如果您想使用关键字作为字段名称，那么只需将其描述为这样。在“描述”（后退字符）

之间

Spring：你的SQL语法有错误;查看与MariaDB服务器版本对应的手册，以获得正确的语法，以便在附近使用

1 个答案: