我在将新发布的数据附加到现有数据时遇到问题。
现在,当点击提交按钮时,它会覆盖'notes'的现有值,仅包含$ header和新的$ _POST [“notes”]值。
我希望它能做的是: $ header + $ _POST [“notes”] + $ notes(现有数据)
这是我目前的代码:
<?php
// Database connection file
include_once("../config.php");
// Get id from url
$id = $_GET['id'];
// Selecting data associated with this id
$sql = "SELECT * FROM testtable WHERE id=:id";
$query = $dbConn->prepare($sql);
$query->execute(array(':id' => $id));
while($row = $query->fetch(PDO::FETCH_ASSOC)){
$notes = $row['notes'];
}
?>
<?php
// Create Header
$header = "----- Updated on " . date("Y-m-d") . " at " . date("h:i:sa") . " ----- <br>";
// Current note data
$currentnotes = $notes;
// Append Header + Post + Current Data
$appendednotes = $header;
$appendednotes .= $_POST["notes"];
$appendednotes .= "<br>";
$appendednotes .= $currentnotes;
if(isset($_POST['update'])){
$id = $_POST['id'];
$notes=$appendednotes;
// Update the table
$sql = "UPDATE testtable SET
notes=:notes
WHERE id=:id";
$query = $dbConn->prepare($sql);
$query->bindparam(':id', $id);
$query->bindparam(':notes', $notes);
$query->execute();
// Redirect to the display page
header("Location: index.php");
}
?>
这是找到我想要做的最接近的例子,但我不确定如何调整它: php post to variable and then append to txt
答案 0 :(得分:0)
感谢Paul,我将我的代码更新到了这个并且它有效!
// Update the table
$sql = "UPDATE survey SET
notes=concat(:notes, notes)
WHERE id=:id";