我有一个可变项,其中包括贷款期限,只有两种类型:" 36个月"和#34; 60个月"。我想过滤我的数据集df并为这些类别创建两个不同的子集。
我尝试过使用命令子集,过滤器等等,但它没有用。
代码我尝试df1 –> df[which(df$term == "36 months"),]
,df1 –> filter(df, term == "36 months")
df1–>df[df$term %in% c("36 months"), ]
以及其他方式,但始终选择零行。
head(loan_data$term)
[1]" 36个月" " 60个月" " 36个月" " 36个月" " 60个月" " 36个月"
有什么建议吗?
由于
答案 0 :(得分:1)
我无法重现您的问题:
df <- data.frame(
id = c(1, 2, 3),
val = c("60 months", "36 months", "60 months")
)
df[df$val == "60 months", ]
# df$val == "60 months"
# 1 1 60 months
# 3 3 60 months
df[which(df$val == "60 months"),]
# df$val == "60 months"
# 1 1 60 months
# 3 3 60 months
答案 1 :(得分:0)
更强有力地解释here,使用...
my.data.frame %>% filter(.data[[myName]] == 1) ...
df60 <- df %>% filter(.df[[term]] == "60 months")
df30 <- df %>% filter(.df[[term]] == "30 months")
...或here
ssP <- mutate( nino, PHASE = ifelse(PHASE == "E", "N","L"))
哪个适合您的 df ..
df60 <- mutate( df, term = ifelse(term == "60 months"))
df30 <- mutate( df, term = ifelse(term == "30 months"))