Question

我的装饰工作得很好，现在存放在一个模块中。如果可能的话，我希望将其存储在类中，而不是将其存放在相关功能中。但是，我似乎无法让它工作，这是代码（没有相关的部分）：

class MqPubSubFwdController(object):

    def __init__(self, address, port_pub, port_sub):

        self.mq_path_list = []
        self.mq_path_func = {}

    def handle_mq(self, mq_path, cmd=None):
        """ Decorator function.
            Registers the MQ path
        """
        def decorator(fn):
            key = "my_key"
            self.mq_path_list.append(prepostfix(mq_path).lower())
            self.mq_path_func[key] = fn

            def decorated(*args,**kwargs):
                return fn(*args,**kwargs)
            return decorated
        return decorator

@messaging.handle_mq('/mode/set','PUT')
def mq_mode_set(path=None, cmd=None, args=None, data=None):
    """ Set mode """
    print "A MODE WAS SET"
    return "A MODE WAS SET"

messaging = MqPubSubFwdController('localhost',1,2)

这将返回错误 NameError：name＆＃39; messaging＆＃39;未在@ -decorator上定义。有没有办法让它工作，以便我可以在课堂上调用装饰器功能？我是Python 2.7。

Answer 1

就像Aran-Fey所说的那样，关于这个位置。在引用其中的装饰器函数之前，需要初始化该类。

这是正确的代码：

class MqPubSubFwdController(object):

    def __init__(self, address, port_pub, port_sub):

        self.mq_path_list = []
        self.mq_path_func = {}

    def handle_mq(self, mq_path, cmd=None):
        """ Decorator function.
            Registers the MQ path
        """
        def decorator(fn):
            key = "my_key"
            self.mq_path_list.append(mq_path.lower())
            self.mq_path_func[key] = fn

            def decorated(*args,**kwargs):
                return fn(*args,**kwargs)
            return decorated
        return decorator

messaging = MqPubSubFwdController('localhost',1,2)

@messaging.handle_mq('/mode/set','PUT')
def mq_mode_set(path=None, cmd=None, args=None, data=None):
    """ Set mode """
    print "A MODE WAS SET"
    return "A MODE WAS SET"

Python：在一个类中存储装饰器？

1 个答案: