如何用awk对重复行的值求和?

时间:2018-06-07 19:27:37

标签: awk

我有一个包含11行的csv文件:

Order Date,Username,Order Number,No Resi,Quantity,Title,Update Date,Status,Price Per Item,Status Tracking,Alamat
05 Jun 2018,Mildred@email.com,205583995140400,,2,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Syahrul Address
05 Jun 2018,Mildred@email.com,205583995140400,,1,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Syahrul Address
05 Jun 2018,Martha@email.com,205486016644400,,2,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Faishal  Address
05 Jun 2018,Martha@email.com,205486016644400,,2,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Faishal  Address
05 Jun 2018,Misty@email.com,205588935534900,,2,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Rutwan Address
05 Jun 2018,Misty@email.com,205588935534900,,1,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Rutwan Address

我想删除该文件中的重复项,并对Quantity行中的值求和。我希望结果是这样的:

Order Date,Username,Order Number,No Resi,Quantity,Title,Update Date,Status,Price Per Item,Status Tracking,Alamat
05 Jun 2018,Mildred@email.com,205583995140400,,3,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Syahrul Address
05 Jun 2018,Martha@email.com,205486016644400,,4,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Faishal  Address
05 Jun 2018,Misty@email.com,205588935534900,,3,Gold,05 Jun 2018 – 10:01,In Process,Rp3.000.000,Done,Rutwan Address

我只想对Quantity行中的值求和,而其余部分保持不变。我已经在this question中尝试了解决方案但是只有文件只有2行才有效,我有11行,所以它不起作用。我如何用awk做到这一点?

2 个答案:

答案 0 :(得分:5)

awk救援!

$ awk 'BEGIN{FS=OFS=","} 
       NR==1{print; next} 
            {q=$5; $5="~"; a[$0]+=q} 
       END  {for(k in a) {sub("~",a[k],k); print k}}' file

Order Date,Username,Order Number,No Resi,Quantity,Title,Update Date,Status,Price Per Item,Status Tracking,Alamat
05 Jun 2018,Misty@email.com,205588935534900,,3,Gold,05 Jun 2018 - 10:01,In Process,Rp3.000.000,Done,Rutwan Address
05 Jun 2018,Martha@email.com,205486016644400,,4,Gold,05 Jun 2018 - 10:01,In Process,Rp3.000.000,Done,Faishal  Address
05 Jun 2018,Mildred@email.com,205583995140400,,3,Gold,05 Jun 2018 - 10:01,In Process,Rp3.000.000,Done,Syahrul Address

请注意,记录的顺序无法保证,但也不要求最初对它们进行排序。为了保留订单,有多种解决方案......

另外,我使用~作为占位符。如果您的数据包含此字符,则可以替换为未使用的字符。

<强>更新

保留订单(基于第一次出现的行)

$ awk 'BEGIN{FS=OFS=","} 
       NR==1{print; next} 
            {q=$5;$5="~"; if(!($0 in a)) b[++c]=$0; a[$0]+=q} 
       END  {for(k=1;k<=c;k++) {sub("~",a[b[k]],b[k]); print b[k]}}' file

保留一个单独的结构来标记行的顺序并迭代该数据结构......

答案 1 :(得分:1)

直接适应Karafka的解决方案并在其中添加一些代码,以便按照OP的请求以正确的顺序(它们存在于Input_file中)获得行。

awk -F, '
FNR==1{
  print;
  next}
{
  val=$5;
  $5="~";
  a[$0]+=val
}
!b[$0]++{
  c[++count]=$0}
END{
  for(i=1;i<=count;i++){
     sub("~",a[c[i]],c[i]);
     print c[i]}
}' OFS=,   Input_file

说明: 现在也向上面的代码添加说明。

awk -F, '                         ##Setting field separator as comma here.
FNR==1{                           ##Checking condition if line number is 1 then do following.
  print;                          ##Print the current line.
  next}                           ##next will skip all further statements from here.
{
  val=$5;                         ##Creating a variable named val whose value is 5th field of current line.
  $5="~";                         ##Setting value of 5th field as ~ here to keep all lines same(to create index for array a).
  a[$0]+=val                      ##Creating an array named a whose index is current line and its value is variable val value.
}
!b[$0]++{                         ##Checking if array b whose index is current line its value is NULL then do following.
  c[++count]=$0}                  ##Creating an array named c whose index is variable count increasing value with 1 and value is current line.
END{                              ##Starting END block of awk code here.
  for(i=1;i<=count;i++){          ##Starting a for loop whose value starts from 1 to till value of count variable.
     sub("~",a[c[i]],c[i]);       ##Substituting ~ in value of array c(which is actually lines value) with value of SUMMED $5.
     print c[i]}                  ##Printing newly value of array c where $5 is now replaced with its actual value.
}' OFS=, Input_file               ##Setting OFS as comma here and mentioning Input_file name here too.