我的代码返回HTTP错误403:禁止

时间:2018-06-07 17:20:25

标签: python beautifulsoup request screen-scraping urllib

from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup

myUrl = "https://mee6.xyz/levels/159962941502783488"

uClient = uReq(myUrl)
pageHtml = uClient.read()
print("pageHtml)

我正在尝试访问一个页面以开始抓取它,但它回复说HTTP是被禁止的,我查找了其他结果,但它们与我正在执行代码的方式不匹配

1 个答案:

答案 0 :(得分:0)

您因用户代理而被阻止。尝试欺骗您的用户代理,如下所示:

from urllib.request import urlopen as uReq
from urllib.request import Request
from bs4 import BeautifulSoup as soup

myUrl = "https://mee6.xyz/levels/159962941502783488"

req = Request(
    myUrl, 
    data=None, 
    headers={
        'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/66.0.3359.181 Safari/537.36'
    }
)

uClient = uReq(req)
pageHtml = uClient.read()
print(pageHtml)