Question

我试图从数据库中删除一条记录，但是ORACLE声称＆＃34;违反了完整性约束 - 找到了儿童记录＆＃34;。

如果我试图找到这个子记录，它在DB中就不存在了。

任何人都知道如何解决这个问题？

SQL> delete from AMZ_SERVCO where ID_SERVCO = 447;

delete from AMZ_SERVCO where ID_SERVCO = 447
*
ERROR at line 1:
ORA-02292: integrity constraint (AMAZONIA.FK_AMZ_FRNQIA_PA_AMZ_SERVCO) violated - child record found

SQL> select table_name from all_tab_columns where column_name='ID_SERVCO';

TABLE_NAME
------------------------------
AMZ_DESCTO_PO_SERVCO_APLCAO
AMZ_DESCTO_PO_SERVCO
BKP151207_AMZ_ARQVO_DESCTO
BKP_ARQVO_DESCTO
AMZ_SERVCO_PO
AMZ_SERVCO_PA
AMZ_SERVCO
AMZ_FRNQIA_PO_SERVCO
AMZ_DESCTO_PO
AMZ_CATEGR_PO
AMZ_CATEGR_PA

TABLE_NAME
------------------------------
AMZ_BONUS_PO
AMZ_ASSTUR_PO
AMZ_ASSTUR_PA
AMZ_ARQVO_SERVCO
AMZ_ARQVO_DESCTO
AMZ_APA_PO
AMZ_APA_PA
AMZ_FRNQIA_PA_SERVCO
AMZ_EXPSAO_ENTDDE_OPRDRA

20 rows selected.

SQL> select * from AMZ_EXPSAO_ENTDDE_OPRDRA WHERE ID_SERVCO = 447;
select * from AMZ_FRNQIA_PA_SERVCO WHERE ID_SERVCO = 447;
select * from AMZ_APA_PA WHERE ID_SERVCO = 447;
select * from AMZ_APA_PO WHERE ID_SERVCO = 447;
select * from AMZ_ARQVO_DESCTO WHERE ID_SERVCO = 447;
select * from AMZ_ARQVO_SERVCO WHERE ID_SERVCO = 447;
select * from AMZ_ASSTUR_PA WHERE ID_SERVCO = 447;
select * from AMZ_ASSTUR_PO WHERE ID_SERVCO = 447;
select * from AMZ_BONUS_PO WHERE ID_SERVCO = 447;
select * from AMZ_CATEGR_PA WHERE ID_SERVCO = 447;
select * from AMZ_CATEGR_PO WHERE ID_SERVCO = 447;
select * from AMZ_DESCTO_PO WHERE ID_SERVCO = 447;
select * from AMZ_FRNQIA_PO_SERVCO WHERE ID_SERVCO = 447;
select * from AMZ_SERVCO WHERE ID_SERVCO = 447;
select * from AMZ_SERVCO_PA WHERE ID_SERVCO = 447;
select * from AMZ_SERVCO_PO WHERE ID_SERVCO = 447;
select * from BKP_ARQVO_DESCTO WHERE ID_SERVCO = 447;
select * from BKP151207_AMZ_ARQVO_DESCTO WHERE ID_SERVCO = 447;
select * from AMZ_DESCTO_PO_SERVCO WHERE ID_SERVCO = 447;
select * from AMZ_DESCTO_PO_SERVCO_APLCAO WHERE ID_SERVCO = 447;

no rows selected

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SQL>
ID_SERVCO NM_SERVCO ID_TP_SERVCO ID_TP_CATEGR
----------------------------------------------------------------- ------------ ------------
   447 eClaro DDD Nacional                                                                                             5            0

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Answer 1

是的，您需要在所有约束列表中查找违反的约束：

SELECT r_owner, r_constraint_name
  FROM all_constraints 
 WHERE owner='AMAZONIA'
   AND constraint_name='FK_AMZ_FRNQIA_PA_AMZ_SERVCO';

这是父表的主键或唯一键的名称。要查找它的列，您可以使用：

SELECT column_name
  FROM all_cons_columns
 WHERE owner = xxx
   AND constraint_name = yyy;

Answer 2

听起来你可能有另一个你不知道的外键：尝试this solution获取所有外键的列表。对于像这样的复杂系统，我尝试包含[IsActive]布尔列 - 而不是删除可能有子节点的记录，只需将其标记为非活动状态。 HTH！

ORACLE - 找不到子记录

2 个答案: