我试图从以下html中提取链接。 HTML中有很多像这样的HTML。
推文[0]是:
var tweets = Array.from(document.querySelectorAll("[class ^= AdaptiveMedia-ph]"));
console.log(tweets);

<div class="AdaptiveMedia-photoContainer js-adaptive-photo " data-image-url="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" data-element-context="platform_photo_card" style="background-color:rgba(51,64,18,1.0);" data-dominant-color="[51,64,18]">
<img data-aria-label-part="" src="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" alt="A tree" style="width: 100%; top: -0px;">
</div>
&#13;
如何实际拉动&#34; src&#34;来自&#34; alt&#34;的alt文本从HTML文本?提前致谢!
答案 0 :(得分:2)
像这样:
var tweets = document.querySelectorAll("[class ^= AdaptiveMedia-ph]");
for (var i=0;i<tweets.length;i++) {
console.log("data-image-url",tweets[i].getAttribute("data-image-url"));
var img = tweets[i].querySelector("img");
console.log("image-url",img.src,"alt",img.alt);
}
<div class="AdaptiveMedia-photoContainer js-adaptive-photo " data-image-url="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" data-element-context="platform_photo_card" style="background-color:rgba(51,64,18,1.0);" data-dominant-color="[51,64,18]">
<img data-aria-label-part="" src="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" alt="A tree" style="width: 100%; top: -0px;">
</div>
答案 1 :(得分:1)
如果您直接选择.map()
元素,然后只选择// Select img inside the cards
var tweets = Array.from(document.querySelectorAll("[class ^= AdaptiveMedia-ph] img"));
var imgData = tweets.map(e => ({src: e.src, alt: e.alt}));
console.log(imgData);
结果,会更容易:
<div class="AdaptiveMedia-photoContainer js-adaptive-photo " data-image-url="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" data-element-context="platform_photo_card" style="background-color:rgba(51,64,18,1.0);" data-dominant-color="[51,64,18]">
<img data-aria-label-part="" src="https://pbs.twimg.com/media/DfFmgY6WAAAh0sG.jpg" alt="A tree" style="width: 100%; top: -0px;">
</div>
SELECT
ID,
User,
Hour,
Minute
FROM table
WHERE MOD( Minute, 3 ) = 0
ORDER BY Hour ASC, Minute ASC;