Question

Noob在这里提问，我正在尝试发送带有一个添加的字符串参数的文件。我的上传器类看起来像这样：

 public static void HttpUploadFile(string url, string file, string paramName, string contentType, NameValueCollection nvc)
        {
            string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
            byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");

            HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
            wr.ContentType = "multipart/form-data; boundary=" + boundary;
            wr.Method = "POST";
            wr.KeepAlive = true;
            wr.Credentials = System.Net.CredentialCache.DefaultCredentials;
            Stream rs = wr.GetRequestStream();
            string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}";
            foreach (string key in nvc.Keys)
            {
                rs.Write(boundarybytes, 0, boundarybytes.Length);
                string formitem = string.Format(formdataTemplate, key, nvc[key]);
                byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
                rs.Write(formitembytes, 0, formitembytes.Length);
            }
            rs.Write(boundarybytes, 0, boundarybytes.Length);
            string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n";
            string header = string.Format(headerTemplate, paramName, file, contentType);
            byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
            rs.Write(headerbytes, 0, headerbytes.Length);
            FileStream fileStream = new FileStream(file, FileMode.Open, FileAccess.Read);
            byte[] buffer = new byte[4096];
            int bytesRead = 0;
            while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
            {
                rs.Write(buffer, 0, bytesRead);
            }
            fileStream.Close();
            byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
            rs.Write(trailer, 0, trailer.Length);
            rs.Close();
            WebResponse wresp = null;
            try
            {
                wresp = wr.GetResponse();
                Stream stream2 = wresp.GetResponseStream();
                StreamReader reader2 = new StreamReader(stream2);
               var result = reader2.ReadToEnd();
            }
            catch (Exception ex)
            {
                Program.log.Error(System.Reflection.MethodBase.GetCurrentMethod().Name + " Error occurred while converting file ", ex);
                if (wresp != null)
                {
                    wresp.Close();
                    wresp = null;
                }
            }
            finally
            {
                wr = null;
            }
        }

字符串参数位于NameValueCollection中。现在另一方面，post方法应该如何接收呢？

*另外，在这种混合文件+字符串参数的情况下，内容类型应该是“application / octet-stream”吗？

由于

Answer 1

对于您的情况，您可以创建FileUploadViewModel以包含所有属性，包括IFormFile。将此作为参数类型用于操作方法。默认模型绑定器应该能够为您填充所有内容。

另请参阅您是否需要自定义模型装订器 - {{3}}

.NET WebApi - 如何使用其他参数接收文件？

1 个答案: