Python MySQLdb打印表A中的行，而不是表B中的行

Question

我有两个表，sales_olap和resellers

我需要打印sales_olap表中<{1}}中不存在来自resellers的转销商

例如：

result = cursor.execute("SELECT SO.reseller_name FROM sales_olap AS SO WHERE 
SO.reseller_name!=(SELECT reseller FROM resellers)")
for row in result:
    print row

但我收到的错误是：1242, Subquery returns more than 1 row

我怎样才能让它只打印sales_olap表中resellers表中不存在的经销商名称？

如果我尝试：

    result = cursor.execute("SELECT reseller_name FROM sales_olap WHERE reseller_name NOT IN(SELECT reseller FROM resellers)")
    for row in result:
        print row['reseller_name']

然后我收到错误：TypeError: 'long' object is not iterable

Answer 1

能够通过这种方式实现这一目标：

cursor.execute("SELECT reseller_name FROM sales_olap LEFT JOIN resellers ON sales_olap.reseller_name=resellers.reseller WHERE resellers.reseller IS NULL")
result = cursor.fetchall()

for row, in result:
    print (row)