我想使用Vue.js创建一个简单的天气预报网站,我刚刚学习了这个框架并且之前访问过公共数据。但这次我被卡住了。
我尝试过两种版本的方法来获取数据。
var app = new Vue({
el: "#weather",
data: {
city: '',
weather:[],
date: new Date().toDateString(),
greeting:''
},
methods: {
//method 1
getData: function () {
var city = this.city
$.getJSON("http://api.openweathermap.org/data/2.5/weather?q=" + city + "&units=metric&lang=en&appid=a495404234abce9b5830b1e8d20e90a6",
function (data) {
console.log(data)
});
},
//method 2
getData: function () {
$("#search").keypress(function (e) {
if (e.which == 13) {
var city = $("#search").val();
if (city != " ") {
var url = "http://api.openweathermap.org/data/2.5/weather?q=" + city + "&units=metric&lang=en&appid=a495404234abce9b5830b1e8d20e90a6";
console.log(url);
}
$.getJSON(url, function (data) {
this.weather = data.weather;
console.log(data);
this.returnGreeting();
})
}
})
},
}
}
});
<div class="container" id="weather">
<h1>Weather Pro</h1>
<div class="float-left"><h2>{{date}}</h2></div>
<div class="float-right" ><h3 id="time"></h3></div>
<p>{{greeting}}</p>
<div class="input-group">
<form>
<input v-model="city" class='searchbar transparent' id='search' type='text' placeholder=' enter city' />
<input id='button' @click="getData" type="button" value='GO' />
</form>
</div>
{{city}}
<div class="panel">
<div class="panel-body" v-for="d in data">
<p>
{{data}}
</p>
</div>
<ul class="list-group list-group-flush">
<!-- <li class="list-group-item">{{data.weather[0].main}}</li>
<li class="list-group-item">{{data.weather[0].description}}</li> -->
</ul>
</div>
</div>
<!-- vue -->
<script src="https://cdn.jsdelivr.net/npm/vue/dist/vue.js"></script>
<!-- jQuery library -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
我收到了一个错误:
[Vue警告]:属性或方法“数据”未在实例上定义,但在呈现期间引用。通过初始化属性,确保此属性在数据选项或基于类的组件中是被动的。请参阅:https://vuejs.org/v2/guide/reactivity.html#Declaring-Reactive-Properties。
答案 0 :(得分:1)
将data
视为您的模特。不要在视图中直接引用data
,而是引用模型上的引用属性。
而不是<div>{{data.city}}</div>
使用<div>{{city}}</div>
var app = new Vue({
el: "#weather",
data() {
return {
city: '',
weather: [],
date: new Date().toDateString(),
greeting: ''
};
},
methods: {
getData() {
fetch("http://api.openweathermap.org/data/2.5/weather?q=" + this.city + "&units=metric&lang=en&appid=a495404234abce9b5830b1e8d20e90a6")
.then(res => res.json())
.then(data => {
this.weather = data.weather;
});
}
}
});
<div class="container" id="weather">
<h1>Weather Pro</h1>
<div class="float-left">
<h2>{{date}}</h2>
</div>
<div class="float-right">
<h3 id="time"></h3>
</div>
<p>{{greeting}}</p>
<div class="input-group">
<form>
<input v-model="city" class='searchbar transparent' id='search' type='text' placeholder=' enter city' />
<input id='button' @click="getData" type="button" value='GO' />
</form>
</div>
{{city}}
<div class="panel">
<div class="panel-body" v-for="d in weather">
<p>
{{d}}
</p>
</div>
<ul class="list-group list-group-flush"></ul>
</div>
</div>
<!-- vue -->
<script src="https://cdn.jsdelivr.net/npm/vue/dist/vue.min.js"></script>
<!-- jQuery library -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
答案 1 :(得分:0)
看起来像是打败了我,但这里是使用jquery调用的版本
如评论中所述,问题是data.data
未定义。因此,在数据内部定义数据,并将result
分配给this.data
。但是,因为它在函数内部并且范围发生变化,所以您需要使用var that = this
存储范围并使用that.data = data
来分配结果
DOM:
<div class="container" id="weather">
<h1>Weather Pro</h1>
<div class="float-left"><h2>{{date}}</h2></div>
<div class="float-right" ><h3 id="time"></h3></div>
<p>{{greeting}}</p>
<div class="input-group">
<form>
<input v-model="city" class='searchbar transparent' id='search' type='text' placeholder=' enter city' />
<input id='button' @click="getData" type="button" value='GO' />
</form>
</div>
{{city}}
<div class="panel">
<div class="panel-body" v-for="d in data">
<p>
{{d}}
</p>
</div>
<ul class="list-group list-group-flush">
</ul>
</div>
</div>
<!-- jQuery library -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
脚本:
var app = new Vue({
el: "#weather",
data: {
city: '',
weather:[],
date: new Date().toDateString(),
greeting:'',
data: null,
},
methods: {
//method 1
getData: function () {
var that = this;
var city = this.city
console.log('getData')
$.getJSON("https://api.openweathermap.org/data/2.5/weather?q=" + city + "&units=metric&lang=en&appid=a495404234abce9b5830b1e8d20e90a6",
function (data) {
console.log(data)
that.data = data;
});
},
}
});
答案 2 :(得分:0)
我发现了导致这些问题的原因:
$.getJSON()
需要min jQuery。