Question

我正在为具有许多相似列的不同表播种多个csv。例如，教师和学生表具有相似的列电子邮件，名称等。所以我想通过将所有常见事物放入变量来缩短我的种子文件，以便：

puts "Seeding teachers.."
File.open("teachers.csv", "r") do |f|
  f.each_with_index do |line, index|
    email, name, teacher_code = line.chomp.split (",")    
  Teacher.create(email: email, name: name, teacher_code: teacher_code)
  end
end

puts "Seeding students.."
File.open("students.csv", "r") do |f|
  f.each_with_index do |line, index|
    email, name, subject = line.chomp.split (",")
  Student.create(email: email, name: name, subject: subject)
  end
end

变为：

def common_data
    [email, mame]
end

def common_params
    ["email: email", "name: name"] # not sure
end

puts "Seeding teachers.."
File.open("teachers.csv", "r") do |f|
  f.each_with_index do |line, index|
    common_data, teacher_code = line.chomp.split (",")    
  Teacher.create(common_params, teacher_code: teacher_code)
  end
end


puts "Seeding students.."
File.open("students.csv", "r") do |f|
  f.each_with_index do |line, index|
    common_data, subject = line.chomp.split (",")
  Student.create(common_params, subject: subject)
  end
end

我收到错误

NameError: undefined local variable or method `email' for main:Object

Answer 1

common_data中出现错误，是吗？因为，在这里：

[email, mame]

（假设“mame”应该是“name”）ruby希望email是变量或方法。但它不是，是吗？

也许你的意思是：

['email', 'name']

或

[:email, :name]

Rails5：如何为种子参数设置变量

1 个答案: