这是我的数据集
的示例head(visite_cliente_date)
CodCliente museo data Month January February March April May June July
1 76330 BORGO E ROCCA MEDIEVALE 2012-12-01 12 0 0 0 0 0 0 0
2 86660 BORGO E ROCCA MEDIEVALE 2012-12-01 12 0 0 0 0 0 0 0
3 87629 BORGO E ROCCA MEDIEVALE 2012-12-01 12 0 0 0 0 0 0 0
4 255734 BORGO E ROCCA MEDIEVALE 2012-12-01 12 0 0 0 0 0 0 0
5 1496 GAM - GALLERIA CIVICA ARTE MODERNA E C 2012-12-01 12 0 0 0 0 0 0 0
6 16689 GAM - GALLERIA CIVICA ARTE MODERNA E C 2012-12-01 12 0 0 0 0 0 0 0
August September October November Dicember
1 0 0 0 0 1
2 0 0 0 0 1
3 0 0 0 0 1
4 0 0 0 0 1
5 0 0 0 0 1
6 0 0 0 0 1
CodCliente：ID客户
Mueso：博物馆参观了
数据：访问日期
月：访问月份
每个月：我根据“月份”值
为每个月创建一个假人我想创建一个新变量，其中包含客户去博物馆的月份总和。
示例：如果客户在3月，4月和6月至少去过博物馆一次，则该变量的值为“3”。
示例2：如果客户在六月份去博物馆三次，变量的值为“1”。
提前感谢您的回复！
答案 0 :(得分：0)
我终于做到了，但是很长一段时间
首先，我为每个月创建了一个数据集来总结访问量。 在这里，我发布了我在1月份所做的事情
Gennaio <- subset(visite_cliente_date, January == 1)
Gennaio$Month <- NULL
Gennaio$February <- NULL
Gennaio$March <- NULL
Gennaio$April <- NULL
Gennaio$May <- NULL
Gennaio$June <- NULL
Gennaio$July <- NULL
Gennaio$August <- NULL
Gennaio$September <- NULL
Gennaio$October <- NULL
Gennaio$November <- NULL
Gennaio$Dicember <- NULL
Gennaio <- aggregate(Gennaio$January, list("ID" = Gennaio$CodCliente), sum)
Gennaio$January <- Gennaio$x
Gennaio$x <- NULL
head(Gennaio)
ID January
1 41 1
2 94 1
3 106 5
4 111 1
5 113 1
6 118 1
然后我合并了所有数据集，将NA值替换为0
> Visite_mesi <- merge(Gennaio, Febbraio, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Marzo, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Aprile, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Maggio, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Giugno, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Luglio, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Agosto, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Settembre, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Ottobre, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Novembre, by="ID", all=TRUE)
> Visite_mesi <- merge(Visite_mesi, Dicembre, by="ID", all=TRUE)
> Visite_mesi[is.na(Visite_mesi)] <- 0
>
> head(Visite_mesi)
ID January February March April May June July August September
1 41 1 0 0 0 0 0 0 0 0
2 94 1 2 1 1 1 1 0 0 0
3 106 5 9 6 3 4 6 1 7 7
4 111 1 3 1 1 3 5 0 0 0
5 113 1 1 0 0 0 0 0 0 3
6 118 1 0 1 1 0 1 0 1 0
October November Dicember
1 0 0 0
2 1 0 0
3 3 4 5
4 0 0 0
5 0 0 0
6 0 0 0
最后，I转换值大于2 in 1
Visite_mesi$January[Visite_mesi$January >= 2] <- 1
Visite_mesi$February[Visite_mesi$February >= 2] <- 1
Visite_mesi$March[Visite_mesi$March >= 2] <- 1
Visite_mesi$April[Visite_mesi$April >= 2] <- 1
Visite_mesi$May[Visite_mesi$May >= 2] <- 1
Visite_mesi$June[Visite_mesi$June >= 2] <- 1
Visite_mesi$July[Visite_mesi$July >= 2] <- 1
Visite_mesi$August[Visite_mesi$August >= 2] <- 1
Visite_mesi$September[Visite_mesi$September >= 2] <- 1
Visite_mesi$October[Visite_mesi$October >= 2] <- 1
Visite_mesi$November[Visite_mesi$November >= 2] <- 1
Visite_mesi$Dicember[Visite_mesi$Dicember >= 2] <- 1
最后我只是总结了月份列中的所有值，所以我创建了我想要的变量
> Visite_mesi$sum_month <- rowSums( Visite_mesi[,2:13] )
> head(Visite_mesi)
ID January February March April May June July August September
1 41 1 0 0 0 0 0 0 0 0
2 94 1 1 1 1 1 1 0 0 0
3 106 1 1 1 1 1 1 1 1 1
4 111 1 1 1 1 1 1 0 0 0
5 113 1 1 0 0 0 0 0 0 1
6 118 1 0 1 1 0 1 0 1 0
October November Dicember sum_month
1 0 0 0 1
2 1 0 0 7
3 1 1 1 12
4 0 0 0 6
5 0 0 0 3
6 0 0 0 5