Question

我想从同一个列表中选择两个单独的随机选项。有没有办法做到这一点，不包括制作单独的名单？

import random


cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
cards = random.choice(cards)

suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']
suits = random.choice(suits)

first_card = ("your first card is the {} of {}") .format(cards,suits)
second_card = ("your second card is the {} of {}") .format(cards,suits)

print first_card
print second_card

输出

your first card is the 10 of Spades
your second card is the 10 of Spades

我希望输出相同，但最后一张牌与第一张牌不同;两张单独的卡

Answer 1

预先生成所有来自数字和套装的牌，例如列表理解。然后使用random.sample选择两张随机卡片。

import random

figures = [2, 3, 4, 5, 6, 7, 8, 9, 10, 'King', 'Queen', 'Jack']
suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']

cards = [(figure, suit) for figure in figures for suit in suits]

print(random.sample(cards, 2)) # [(5, 'Hearts'), (7, 'Diamonds')]

虽然，我建议你不要混合整数和字符串来定义你的数字，因为这可能会导致一些混乱。我建议您将整数11，12和13分别分配给Jack，Queen和King。

Answer 2

你可以使用itertools生成所有组合然后随机播放列表并取两个，我为n_samples设计了函数你可以选择n个样本：

import random
import itertools

cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']


suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']

def n_random(list_1,list_2,no_of_samples):
    all_possible=[i for i in itertools.product(list_1,list_2)]
    if no_of_samples>len(all_possible):
        return 'Wrong choice'
    else:
        random.shuffle(all_possible)
        return all_possible[:2]

print(n_random(cards,suits,2))

输出：

[(3, 'Diamonds'), (2, 'Spades')]

Answer 3

使用random.sample。

random.sample(population, k)：

返回从人口序列或集合中选择的唯一元素的k长度列表。

import random

cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
chosen_cards = random.sample(cards,2)

suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']
chosen_suits = random.sample(suits,2)

first_card = ("your first card is the {} of {}") .format(chosen_cards[0],chosen_suits[0])
second_card = ("your second card is the {} of {}") .format(chosen_cards[1],chosen_suits[1])

print(first_card)
print(second_card)

Answer 4

每次都可以保证使用不同的卡片：

from random import randint
cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
first_card = cards[randint(0, len(cards)-1)]
second_card = cards[randint(0, len(cards)-1)]
while second_card == first_card:
   second_card = cards[randint(0, len(cards)-1)]
print first_card
print second_card

在卡列表中选择多个随机项

输出

4 个答案: