Question

我的整个代码是：

import itertools as it
import numpy as np
import scipy
from scipy import special
for q in [29, 37, 53, 61]:
    p = int((q-1)/4)
    d0 = [2**(4*i) % q for i in range(p)]
    d2 = [2**(4*i + 2) % q for i in range(p)]
    c2 = list(it.combinations(d0,2))
    cd = list(it.combinations(d2,p-2))
    s2 = [sum(c2[i]) % q for i in range(len(c2))]
    sd = [sum(cd[i]) % q for i in range(len(cd))]
    a = [i for i,x in enumerate(s2) if x == 1]
    b = [i for i,x in enumerate(sd) if x == 1]
    l = [list(c2[i]) for i in a]
    l1 = [list(cd[i]) for i in b]
    c = [[d0.index(l[i][j]) for j in range(2)] for i in range(len(l))]
    d = [[d2.index(l1[i][j]) for j in range(p-2)] for i in range(len(l1))]
    cp = [[4*c[i][j] for j in range(2)] for i in range(len(c))]
    dp = [[4*d[i][j]+2 for j in range(p-2)] for i in range(len(d))]
    dps = [set(x) for x in dp]
    dpp = [4*i+2 %q for i in range(p)]
    cop_dpp = []
    for i in range(len(dp)):
        cop_dpp.append(dpp)
    cop_dpps = [set(x) for x in cop_dpp]
    diff = [cop_dpps[i] - dps[i] for i in range(len(dp))]
    diffl = [list(x) for x in diff]
    e = []
    for i in range(len(cp)):
        for o in range(len(cp)):
            x = cp[i] + diffl[o]
            e.append(x)
    f = []
    for k in range(1):
        for l in range(1):
            x = e[k] + e[l]
            f.append(x)
print(q,cp)
print(q, diffl)
print(q,e)
print(q,f)

它给出的错误是：

f = []
    ^
IndentationError: unindent does not match any outer indentation level

我试过在每个地方移动f = []。在代码中的不同位置标记它（以及它所依赖的for循环），但获得相同的错误。写了一段简单的代码：

a = [[1,2,3]]
b = [[3,4,5]]
e = []
for i in range(len(a)):
    for o in range(len(b)):
        x = a[i] + b[o]
        e.append(x)
f = []
for k in range(len(e)):
    for l in range(len(e)):
        x = e[k] + e[l]
        f.append(x)
print(e)
print(f)

运行正常。我已经为每行代码使用了制表符。任何帮助将非常感激。先感谢您！

Answer 1

在文本编辑器或IDE中找到允许您查看空格的设置 - 这将帮助您查看代码中选项卡和空格之间的区别。正如有人在评论中所说，如果你有混合（例如当文本编辑器中的默认值与你本能地做的不同时会发生），python将无法计算出你的缩进。

缩进错误：unindent与任何外部缩进级别都不匹配[所有选项卡]

1 个答案: