Question

我的用户类包含字段名字，姓氏，性别，电子邮件，密码，DOB，地址和角色。

@Entity
@Table(name="User_s180")
public class User {

@Id
private String Email;

@Column(nullable=false)
private String FirstName;

private String LastName;

@Column(nullable=false)
private String Gender;

@Column(nullable=false)
private String Mobile_Number;

@Column(nullable=false)
private Date DOB;

@Column(nullable=false)
private String Address; 

@Column(nullable=false)
private String Password;

@Column(nullable=false)
private String Role;

@Column(name="Online_status")
private boolean Online;

我在这里有所有领域的getter和setter

我想创建电子邮件作为我的主键，因此我有@Id但是因为它是字符串类型我不能使用@Generation注释。每当我尝试在Db中插入一个新用户时我得到一个错误嵌套异常是org.hibernate.id.IdentifierGenerationException：在根本原因调用save（）：com.niit.model.User]之前必须手动分配此类的ID

Hibernate代码

package com.niit.Dao;

import org.hibernate.Query;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;

import com.niit.model.User;

@Repository
@Transactional
public class UserDaoImpl implements UserDao {
@Autowired
private SessionFactory sf;

public  UserDaoImpl()
{
    System.out.println("UserDaoImpl is Instantiated");
}

public void Registration(User user) {
    Session ssn=sf.getCurrentSession();
    ssn.save(user);
    }

public boolean isEmailUnique(String email) {
    // TODO Auto-generated method stub
    Session ssn=sf.getCurrentSession();
    Query query=ssn.createQuery("from User where email=:email");
    query.setString("email",email);
    User user=(User)query.uniqueResult();

    //User already exists
    if(user!=null)  
    {
    return  false;
    }
    else
    {
    return  true;
    } 

}

public User Login(User user) {
    // TODO Auto-generated method stub
    Session ssn=sf.getCurrentSession();
    Query query=ssn.createQuery("from User where email=:email and password=:password");
    query.setString("email",user.getEmail());
    query.setString("password", user.getPassword());
    User validuser=(User)query.uniqueResult();
    return validuser;

}

public void UpdateUserOnlineStatus(User user) {
    // TODO Auto-generated method stub
    Session ssn=sf.getCurrentSession();
    ssn.update(user);

}

}

控制器类

package com.niit.controllers;


import javax.servlet.http.HttpSession;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

import com.niit.Dao.UserDao;
import com.niit.model.Errorclass;
import com.niit.model.User;

@Controller
public class UserController {
@Autowired
private UserDao userdao;


public UserController(){
    System.out.println("UserController is instantiated");
}

@RequestMapping(value="/Signupuser",method=RequestMethod.POST)
public ResponseEntity<?> Registration(@RequestBody User user){
System.out.println("Registration function invoked");

    if(userdao.isEmailUnique(user.getEmail()))
    {  
        System.out.println("Email is Unique --> Registering User");
        userdao.Registration(user);
        System.out.println("User Registered Successfully");
        return new ResponseEntity<User>(user,HttpStatus.OK);
    }
    else
    {   
        System.out.println("Email is not Unique --> User cannot be Registered");
        Errorclass ec=new Errorclass(10,"Email-id already exists");
        return new ResponseEntity<Errorclass>(ec,HttpStatus.CONFLICT);
    }

}

Answer 1

if（userdao.isEmailUnique（user.getEmail（）））检查不足以确保您在请求中收到了有效的电子邮件地址。如果电子邮件为空，您的查询将转换为＆＃34;来自用户，其中email = null＆＃34;。

尝试在UserDaoImpl.Registration方法中打印User类，并确保您有一个电子邮件地址。

在调用save（）之前，必须手动分配此类的ID;

1 个答案: