使用RegEx将大写设置为tittle（）

Question

我需要在文本中找到所有大写的单词并将其标题化。我一直试图用re.sub做这个，但我无法弄清楚第二个参数应该是什么。我试过了：

import re

text = """
This is SOME text that I HAVE to change
I hope it WOULD work pretty EASY"""

pattern = r'(?P<b>[A-Z])(?P<a>[A-Z]+)'

re.sub(pattern, pattern.title(), text)

print(text)

我想我需要将匹配对象作为第二个参数传递，但我不知道该怎么做。

Answer 1

您可以使用

import re

text = """This is SOME text that I HAVE to change
I hope it WOULD work pretty EASY"""
pattern = r'\b[A-Z]{2,}\b'
text = re.sub(pattern, lambda x: x.group().title(), text)
print(text)

请参阅Python demo让步

This is Some text that I Have to change
I hope it Would work pretty Easy

\b[A-Z]{2,}\b regex匹配单词边界内的任何2个或更多大写ASCII字母（作为整个单词）。在lambda表达式中，使用m.group()访问匹配值，并在使用title()方法修改后将其作为替换值返回。