Question

我开始学习Netwroking的Moya

在实施TargetType

期间需要

是否有办法不为每个终点提供样本数据

而且，我无法找到启用/禁用样本数据的方法。

var sampleData: Data {
    switch self {
    case .zen:
        return "Half measures are as bad as nothing at all.".utf8Encoded
    case .showUser(let id):
        return "{\"id\": \(id), \"first_name\": \"Harry\", \"last_name\": \"Potter\"}".utf8Encoded
    case .createUser(let firstName, let lastName):
        return "{\"id\": 100, \"first_name\": \"\(firstName)\", \"last_name\": \"\(lastName)\"}".utf8Encoded
    case .updateUser(let id, let firstName, let lastName):
        return "{\"id\": \(id), \"first_name\": \"\(firstName)\", \"last_name\": \"\(lastName)\"}".utf8Encoded
    case .showAccounts:
        // Provided you have a file named accounts.json in your bundle.
        guard let url = Bundle.main.url(forResource: "accounts", withExtension: "json"),
            let data = try? Data(contentsOf: url) else {
                return Data()
        }
        return data
    }
}

我怎么做？

答案

static let provider = MoyaProvider<VMAPI>.init(stubClosure: MoyaProvider<VMAPI>.immediatelyStub)

Answer 1

要在Moya中禁用或启用示例数据，我们应该使用必需状态初始化提供程序。

static let provider = MoyaProvider<VMAPI>.init(stubClosure: MoyaProvider<VMAPI>.immediatelyStub)

Answer 2

如果你想忽略简单数据

  var sampleData: Data {
           return "There is No smaple Data".data(using: String.Encoding.utf8)!
    }

或者如果你想使用简单的数据就像你在问题中那样做

Answer 3

在moya中为sampleData尝试此代码

var sampleData: Data {
        switch self {
        case .login(_,_):
            return "Half measures are as bad as nothing at all.".utf8Encoded

        default:
            return Data()
        }
    }

Moya - 如何启用样本数据？

3 个答案: