Question

我正在制作一款有2种游戏模式（redMode和blueMode）的射击游戏。这两种模式是ViewController，有subView（UIView子类）和游戏结果视图，显示你得分的数量。
但是有一些差异取决于游戏模式。我试图制作“ResultView Class”，并希望让这两种游戏模式拥有该类。但我不知道如何分开处理取决于游戏模式。

理想：

制作“ResultView类”
在“showResultView”函数中以每种游戏模式（RedView和BlueView）制作ResultView
分开一些处理取决于游戏模式

（现在我在每个游戏模式中制作“resultView”，即使内容几乎相同“）

我该如何解决？

//ViewController for RedMode
class RedGameViewController: UIViewController {

var gameStatus: status!
var redView: RedView!

    override init(frame: CGRect) {
    super.init(frame: frame)

    redView = RedView.init(frame: CGRect(x: 0, y: 0, width: UIScreen.main.bounds.size.width, height: 568))
    self.view.addSubview(redView)
    redView.redGameViewController = self
    //.....
    }

enum status: String {
    case isPlaying = "isPlaying"
    case isPausing = "isPausing"
    case isGameOver = "isGameOver"
    }

class RedView: UIView {

    weak var redGameViewController: RedGameViewController!

    override init(frame: CGRect) {
     super.init(frame: frame)
    }
    //....
    @objc func showResultView(){ 
        var resultView = UIImageView(frame: CGRect(x: 0, y: 0, width: UIScreen.main.bounds.size.width, height: 568))
        resultView.isUserInteractionEnabled = true
        resultView.image = UIImage(named:"resultView_BG")!
        self.addSubview(resultView)

        resultScoreLabel.text = String(score)
        resultBackToTopBtn.isHidden = false
        if redViewController.gameStatus == .isGameOver {
            print("isGameOver")
        }else{
            print("Clear")
        }
    }
}
//ViewController for BlueMode
class BlueGameViewController: UIViewController {

var gameStatus: status!
var blueView: BlueView!

    override init(frame: CGRect) {
    super.init(frame: frame)

    blueView = BlueView.init(frame: CGRect(x: 0, y: 0, width: UIScreen.main.bounds.size.width, height: 568))
    self.view.addSubview(blueView)
    blueView.blueGameViewController = self
    //.....
    }
enum status: String {
    case isPlaying = "isPlaying"
    case isPausing = "isPausing"
    case isGameOver = "isGameOver"
    }

class BlueView: UIView {

    weak var blueGameViewController: BlueGameViewController!
    override init(frame: CGRect) {

    super.init(frame: frame)
    }
    //....
    @objc func showResultView(){ 
        var resultView = UIImageView(frame: CGRect(x: 0, y: 0, width: UIScreen.main.bounds.size.width, height: 568))
        resultView.isUserInteractionEnabled = true
        resultView.image = UIImage(named:"resultView_BG")!
        self.addSubview(resultView)

        //Different from showResultView in RedView
        resultScoreLabel.text = String(score*10)
        resultBackToTopBtn.isHidden = true
        if blueViewController.gameStatus == .pausing {
            print("isPausing")
        }else{
            print("Clear")
        }
    }
}

Answer 1

这样做的好方法是使用协议。

选项1：

假设您有一个名为ColoredView的协议，其中包含您的逻辑方法

protocol ColoredView {
     func showResult(/* add parameters if you need them */)
}

在名为ResultViewController的UIViewController中，您将拥有一个能够调用逻辑函数的ColoredView，如

class ResultViewController {
     var coloredView: UIView!

     func showResultView() {
          guard let coloredView = self.coloredView as? ColoredView else {
              // This is not a coloredView
              return
          }
          coloredView.showResult()
     }
}

由此，只需创建实现协议的两个视图

class RedView: UIView, ColoredView {
    func showResult() {
        // Insert Red logic here
    }
}

class BlueView: UIView, ColoredView {
    func showResult() {
        // Insert Blue logic here
    }
}

然后使用RedView或BlueView创建ResultViewController作为其coloredView。

选项2：

您可以使用

等协议分离变量

protocol ColoredView {
     func getScoreText(from score: Int) -> String
     func getPrintText(for status: Status) -> String
     var isHidden: Bool
}

就像选项1

一样

func showResult() {
    if let coloredView = self.coloredView as? ColoredView {
        resultScoreLabel.text = coloredView.getScoreText(from: score)
        resultBackToTopBtn.isHidden = coloredView.isHidden
        print(coloredView.getPrintText(for: gameStatus)
    }
}

用

class RedView: UIView, ColoredView {
     func getScoreText(from score: Int) -> String {
         // Insert Red logic here
    }

    var isHidden = false

    func getPrintText(for status: Status) -> String {
         // Insert Red logic here
    }
}

class BlueView: UIView, ColoredView {
     func getScoreText(from score: Int) -> String {
         // Insert Blue logic here
    }

    var isHidden = true

    func getPrintText(for status: Status) -> String {
         // Insert Blue logic here
    }
}

希望它有所帮助;）

如何检查Swift中子类中使用的ViewController

1 个答案: