我有JSON结构:
"periods": {
"2018-06-07": [
{
"firstName": "Test1",
"lastName": "Test1"
}
],
"2018-06-06": [
{
"firstName": "Test1",
"lastName": "Test1"
}
]
}
我试着像这样解析它:
public struct Schedule: Codable {
public let periods: Periods
}
public struct Periods: Codable {
public let unknown: [Inner]
public struct Inner: Codable {
public let firstName: String
public let lastName: String
}
private struct CustomCodingKeys: CodingKey {
var stringValue: String
init?(stringValue: String) {
self.stringValue = stringValue
}
var intValue: Int?
init?(intValue: Int) {
return nil
}
}
public init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CustomCodingKeys.self)
self.unknown = try container.decode([Inner].self, forKey: CustomCodingKeys(stringValue: "2018-06-06")
}
}
但我只能获得一个值的结果(2018-06-06)。我在这里有多个日期要解析。这可能吗?
答案 0 :(得分:3)
假设您遗漏了围绕此块的{
和}
并且这是有效的JSON所必需的,以下是解析内容的最简单的解决方案,你真的不因为你的名字与JSON中的键匹配所以需要处理CodingKey
,所以合成的CodingKey
可以正常工作:
public struct Schedule: Codable {
public let periods : [String:[Inner]]
}
public struct Inner: Codable {
public let firstName: String
public let lastName: String
}
let schedule = try? JSONDecoder().decode(Schedule.self, from: json)
print(schedule?.periods.keys)
print(schedule?.periods["2018-06-07"]?[0].lastName)
关键是外部JSON是一个JSON对象(字典/地图),只有一个键periods
该键的值是另一个数组映射。就这样打破它,一切都会自动消失。
答案 1 :(得分:2)
好的,所以我想出来就是这样:
public struct Schedule: Codable {
public let periods: Periods
}
public struct Periods: Codable {
public var innerArray: [String: [Inner]]
public struct Inner: Codable {
public let firstName: String
public let lastName: String
}
private struct CustomCodingKeys: CodingKey {
var stringValue: String
init?(stringValue: String) {
self.stringValue = stringValue
}
var intValue: Int?
init?(intValue: Int) {
return nil
}
}
public init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CustomCodingKeys.self)
self.innerArray = [String: [Inner]]()
for key in container.allKeys {
let value = try container.decode([Inner].self, forKey: CustomCodingKeys(stringValue: key.stringValue)!)
self.innerArray[key.stringValue] = value
}
}
结果我得到了这样的字典:[“2018-06-06”:[Inner]]其中key是这个Date String,值是Inner。
答案 2 :(得分:0)
我认为JSON的开头应附加{
,结尾应附加}
,以使其成为有效的JSON,然后您可以使用以下代码轻松提取句点:
struct Period: Decodable {
let firstName: String, lastName: String
}
let schedule = try? JSONDecoder().decode([String:[String:[Period]]].self, from: jsonData!)
let periods = schedule?.values.first?.values