Question

我有四个列表，我试图将内容显示在TreeView的{{1}}上。
我目前的问题是只有每个列表中的最后一项显示在视图中我确信它与我如何迭代列表有关，但我很困惑如何让每个单独的列表项显示在树中。

我的树形结构是：

Form

我在树视图所在的Dog Husky huskylist Chiwawa chiwawlist Cat Siamese siameselist Tabby tabbylist的代码：

Form

Answer 1

在c＃Refer here
中创建对象和动态数组
TreeView Basic了解Refer here

在创建子节点时，您将覆盖该实例。你应该维护一个数组中的节点。

        //tree code

        //add husky list
        List<TreeNode> node8 = new List<TreeNode>();
        foreach (var item in huskyList)
        {
            node8.Add(new TreeNode(item.name));
        }

        TreeNode[] husky = node8.ToArray();

        //add chiwawa list
        List<TreeNode> node9 = new List<TreeNode>();
        foreach (var item in chiwawaList)
        {
            node9.Add(new TreeNode(item.name));
        }

        TreeNode[] chiwawa = node9.ToArray();

        //dog breed
        TreeNode node2 = new TreeNode("Husky", husky);
        TreeNode node3 = new TreeNode("Chiwawa", chiwawa);
        TreeNode[] dog = new TreeNode[] { node2, node3 };

        //dog parent
        TreeNode treeNode = new TreeNode("Dogs", dog);
        treeView1.Nodes.Add(treeNode);

        //add tabby list
        List<TreeNode> nodes = new List<TreeNode>();

        foreach (var item in tabbyList)
        {
            nodes.Add(new TreeNode(item.name));
        }

        TreeNode[] tabby =nodes.ToArray();

        //add siamese list
        List<TreeNode> node7 = new List<TreeNode>();
        foreach (var item in siameseList)
        {
            node7.Add(new TreeNode(item.name));
        }

        TreeNode[] siamese = node7.ToArray();

        //cat breed
        TreeNode node4 = new TreeNode("Siamese", siamese);
        TreeNode node5 = new TreeNode("Tabby", tabby);
        TreeNode[] cat = new TreeNode[] { node4, node5 };

        //cat parent
        treeNode = new TreeNode("Cats", cat);
        treeView1.Nodes.Add(treeNode);

或者使用LINQ，您可以像这样创建树

        // Code Using Linq
        TreeNode husky = new TreeNode("Husky", huskyList.Select(x => new TreeNode(x.name)).ToArray());
        TreeNode chiwawa = new TreeNode("Chiwawa", chiwawaList.Select(x => new TreeNode(x.name)).ToArray());
        TreeNode Siamese = new TreeNode("Siamese", siameseList.Select(x => new TreeNode(x.name)).ToArray());
        TreeNode Tabby = new TreeNode("Tabby", tabbyList.Select(x => new TreeNode(x.name)).ToArray());
        //parent nodes
        treeView1.Nodes.AddRange(new[] {
            new TreeNode("Dog", new TreeNode[] { husky, chiwawa }),
            new TreeNode("Cat", new TreeNode[] { Siamese, Tabby })
            });

迭代通过List在TreeView中显示

1 个答案: