Question

使用此代码，我将API与我的项目连接起来。在$sCurloptUrl中是我的API网址，我从中检索了一些数据并将其放在json格式中。我设法检索除time_from和time_to之外的所有内容。我的网址需要如下所示：http://localhost/Something/json.php?json_id=get_measurements&measuringStation_id=551&matter_id=2&data_type=4&time_from=16.5.2018&time_to=18.5.2018如何获取time_from和time_to？

case 'get_measurements':

        $nMeasuringStationID= $_GET['measuringStation_id'];
        $nMatterID = $_GET['matter_id'];
        $nDataType = $_GET['data_type'];
        $sTimeFrom = $_GET['time_from'];
        $sTimeTo = $_GET['time_to'];

        $sCurloptUrl = 'http://iszz.azo.hr/iskzl/rs/podatak/export/json?measuringStation='.$nMeasuringStationID.'&polutant='.$nMatterID.'&dataType='.$nDataType.'&timeFrom='.$sTimeFrom.'&timeTo='.$sTimeTo.'';

        $headers = [
            'Content-Type: application/json',
        ];
        $curl = curl_init();
        curl_setopt_array($curl, array(
            CURLOPT_RETURNTRANSFER => 1,
            CURLOPT_HTTPGET => true,
            CURLOPT_SAFE_UPLOAD => true,
            CURLOPT_HTTPHEADER => $headers,
            CURLOPT_URL => $sCurloptUrl
        ));
        $oResponse = curl_exec($curl);
        curl_close($curl);
        $oResponse = json_decode($oResponse, true);

        //var_dump($oResponse);

        foreach ($oResponse as $Measurements) 
        {
            $oMeasurement = new Measurement( $Measurements['Data']['value'], $Measurements['Data']['measuring_unit'], $Measurements['Data']['time']);
            array_push($oJson, $Measurements);
        }   
    break;

Answer 1

你的网址中有time_from但是你使用timeFrom添加它，并且timeTo和time_to相同所以这将得到你的价值观：

    $sTimeFrom = $_GET['timeFrom'];
    $sTimeTo = $_GET['timeTo'];

PHP - 将日期插入url

1 个答案: