如何从curl请求获取格式化的json？

Question

我使用此代码返回Google API地点数据：

<?php

error_reporting(E_ALL);
ini_set("display_errors", true);

include_once 'configuration.php';

$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'https://maps.googleapis.com/maps/api/place/textsearch/json?query=restaurants+in+Sydney&key='.API_KEY);
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl_handle, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Your application name');
curl_setopt($curl_handle, CURLOPT_HTTPHEADER, array(
        'Content-Type: application/json')
);

$result = curl_exec($curl_handle);
curl_close($curl_handle);
echo $result;

但是我得到了这样的无格式数据：

  

{“html_attributions”：[]，“next_page_token”：   “CpQCBgEAAPvFBhJiIaT9iMCS-miiTKEXeY0Gkdt3psd0DiGaza6x7U_NCaLCCoc6avQy7_VepOtrke7oIfrXC2MFkeDmD2DJt3Hi5j4IEmHyY9lTT0JkvRRLW043khKMhAiz6U5fdG-Ylkp7Uq3E_jWjOjgSoR7sBbTzVcn_PuzeKcRcwHtyV2h-ZpCwY-YH7wBiKogPvrwQYCWN_scs5ZWsoJSgELFFFfvl-oaL6OXCERv1fZM6opKvri1GMK6_aEYjnj4pR92PjJNWaAeroixITFGoj5RDVS4MNPVd-60jdG83ET0JU-XsjiY7TdipReos7gbKQR8eJXZho11sOLKGtTATOVCzPZYpzsbvjFgpzMzAoyEFEhCtyjb8l0hKpZAXk7rKoe4NGhSVJjiMIqDyQPH0hVYJg-IX1p2Rvw”   “结果”：[{“formatted_address”：“529 Kent St，Sydney NSW 2000，   澳大利亚“，”几何“：{”location“：{”lat“： - 33.875154，”lng“：   151.204976}，“viewport”：{“northeast”：{“lat”： - 33.87374772010728，“lng”：151.2065219798927}，“southwest”：{“lat”： - 33.87644737989272，“lng”：151.2038223201073}}}，“icon “：   “https://maps.gstatic.com/mapfiles/place_api/icons/restau

我需要采用这种格式：