在html

时间:2018-06-05 20:42:38

标签: python django

我有以下Django模型。如您所见,每个菌株的目录都是动态的,而Photos_save模型与菌株模型一致(它允许我为每个菌株保存多张照片)。我想详细了解每种菌株和与之相关的图片。您是否可以帮助我完成此任务所需的views.py和HTML代码?我是Django的新手,到目前为止,我已经设法在索引页面上显示该应变的所有信息,包括照片(但我希望用户能够点击每个的名称)紧张并看到详细的视图)。

class Strain(models.Model):
    """;
    Model representing strains.
    """
    type_strain = (
        ('W', 'Wild Type'),
        ('G', 'GMO'),
        ('P', 'Prospected'),
    )

    def strain_directory_path(instance, filename):
        return 'strain_{0}/{1}'.format(instance.strain_name, filename)

    strain_name = models.CharField(max_length=100, blank=False, null=True, default=None)
    strain_description = models.CharField(max_length=500, blank=True, null=True, default=None)
    data_of_generation = models.DateField(null=True, blank=True, default= None)
    strain_source = models.CharField(max_length=500, blank=True, null=True, default=None)
    strain_parent = models.ForeignKey('Strain', null=True, blank = True, on_delete= models.CASCADE, default= None)
    strain_type = models.CharField(max_length=1 , blank=True, null=True, default=None, choices= type_strain)

class Photos_save(models.Model):
    import datetime
    def strain_directory_path(instance, filename):
        return 'strain_{0}/{1}'.format(instance.strain_name, filename)



    strain_name = models.ForeignKey(Strain, on_delete=models.CASCADE, default= None)
    upload_photo = models.FileField(upload_to= strain_directory_path, default= None)
    photo_description = models.CharField(max_length= 200, default= None, blank= True)
    photo_upload_date = models.DateField(blank=True, default=datetime.date.today)


    def __str__(self):
        """
        String for representing the Model object.
        """
        return '{0}'.format(self.strain_name)

    def get_absolute_url(self):
        """
        Returns the url to access a particular photo instance.
        """
        return reverse('photo-detail', args=[str(self.id)])

0 个答案:

没有答案