我有一个如下所示的数组:
0: {ID: null,
name: "test",
city: "Austin",
UserColors: [{color: "blue"},{hobby:"beach"} ... ]}
}...
我正在尝试通过初始数组进行重复 - 但是一旦我尝试遍历列表,我什么也看不见,继承人html / angular
<tr ng-repeat="c in vm.people">
<td>{{c.name}}</td>
<td>{{c.city}}</td>
<td ng-repeat="uc in c.UserColors">
<td>{{uc.color}}</td>
</td>
</tr>
我不确定有什么问题,感谢您的帮助,我提前感谢您。
答案 0 :(得分:1)
我会使用自定义过滤器处理该字段:
return "%014x" % int(x * 16**14)
过滤器:
<td ng-repeat-start="(key, value) in c.UserColors | reduce">
<b>{{key}}</b>
</td>
<td ng-repeat-end>
{{value}}
</td>
app.filter("reduce",function() {
return function(items) {
var x = items.map(o => Object.entries(o));
var x2 = x.reduce(((a,x) => (a.concat(x))), []);
var x3 = x2.reduce(((o,x) => (o[x[0]]=x[1],o)), {});
return x3;
}
})
&#13;
angular.module("app",[])
.controller("ctrl",function(){
var vm = this;
vm.people = {
0: {ID: null,
name: "test",
city: "Austin",
UserColors: [{color: "blue"},{hobby:"beach"}]
},
1: {ID: null,
name: "best",
city: "Boston",
UserColors: [{colorx: "red"},{shirt:"black"}]
},
2: {ID: null,
name: "rest",
city: "Paris",
UserColors: [{colory: "yel"},{fruit:"peach"}]
},
}
})
.filter("reduce",function() {
return function(items) {
var x = items.map(o => Object.entries(o));
var x2 = x.reduce(((a,x) => (a.concat(x))), []);
var x3 = x2.reduce(((o,x) => (o[x[0]]=x[1],o)), {});
return x3;//items;
}
})
&#13;