Question

我有解析后构建最终对象的对象，所以我尝试将tempObject1和tempObject2添加到OrderRequest，但它没有添加到对象。所以我在处理后提到了我想要的输出。

index.ts

export class OrderRequest {
private containingJSON = {"OrderRequest": {}};;
    public rxOrderRequest(_request: any): OrderRequest {

                const tempObject1: object = Object.assign({}, JSON.parse(strInfo));

                const tempObject2: object = Object.assign({}, JSON.parse(strNonType),
                    JSON.parse(strType)
                );
                this.containingJSON['OrderRequest'] = tempObject1;
                this.containingJSON['OrderRequest']= tempObject2


                return this;
            }
}

输出

"OrderRequest": {
        User:{},
        Order: {nonCrittical:Object,critical:object}
}

Answer 1

您在代码中重新分配this.containingJSON [＆＃39; OrderRequest＆＃39;]，而不是创建新属性。根据您的需要，以下是更新的代码

export class OrderRequest {
private containingJSON = {"OrderRequest": {}};;
    public rxOrderRequest(_request: any): OrderRequest {

                const tempObject1: object = Object.assign({}, JSON.parse(strInfo));

                const tempObject2: object = Object.assign({}, JSON.parse(strNonType),
                    JSON.parse(strType)
                );
                this.containingJSON['OrderRequest']['tempObject1'] = tempObject1;// assign tempObject1 to a new property "tempObject1"
                this.containingJSON['OrderRequest']['tempObject2'] = tempObject2;


                return this;
            }
}

如何使用typescript将属性添加到对象？

1 个答案: