Question

我想合并多个在同一个数组中且只有一个对象的对象，我需要在不同的对象中添加具有相同键的元素的值。这是我将使用的数组和对象的一个示例。我不知道钥匙是什么，这使一切变得复杂。我正在使用nodejs。

var array = [{
    RT: 0.3396966806905289,
    Real: 0.03721461991442617,
    fired: 0.26138293747172237,
    'Real Madrid': 0.15767570563383954,
    Madrid: 0.2771992640023346,
    Zidane: 0.3218878635800967,
    'Florentino Perez': 0.31535141126767907,
    leave: 0.1632670522868711,
    manager: 0.12690962022792524,
    tancredipalmeri: 0.3218878635800967,
    Perez: 0.4543985280046692,
    Florentino: 0.44189852800466917
  },
  {
    Cannavaro: 0.2709492640023346,
    Ashley: 0.2771992640023346,
    'Ashley Cole': 0.15767570563383954,
    Casillas: 0.3896966806905289,
    Ronaldo: 0.22094926400233458,
    Zidane: 0.22094926400233458,
    Messi: 0.22094926400233458,
    Lampard: 0.22094926400233458,
    Iniesta: 0.22094926400233458,
    Terry: 0.2771992640023346,
    Henry: 0.19890866571173632,
    Cole: 0.22094926400233458,
    Ivanovic: 0.3218878635800967
  },
  {
    RT: 0.3396966806905289,
    effleurer: 0.22094926400233458,
    'n\'a': 0.2709492640023346,
    top: 0.13189246756926315,
    Zidane: 0.2709492640023346,
    entraineur: 0.22094926400233458,
    monde: 0.22094926400233458,
    au: 0.2271992640023346,
    'au monde': 0.20434237230050623,
    Mvssi10: 0.3218878635800967,
    JAMAIS: 0.2709492640023346
  },
  {
    RT: 0.3396966806905289,
    Real: 0.10790900513119943,
    FrenchRMCF: 0.3218878635800967,
    en: 0.2271992640023346,
    histoire: 0.2709492640023346,
    coach: 0.2271992640023346,
    au: 0.2271992640023346,
    Zidane: 0.22094926400233458,
    'en tant': 0.15767570563383954,
    tant: 0.22094926400233458
  }
]

Answer 1

您可以使用reduce来迭代每个对象的对象键：

const res = array.reduce((a, b) => {
    Object.keys(b).forEach(k => {
        a[k] = (a[k] || 0) + b[k];
    });
    return a;
}, Object.create(null));

console.log(res);

<script>
const array = [
    {
        RT: 0.3396966806905289,
        Real: 0.03721461991442617,
        fired: 0.26138293747172237,
        'Real Madrid': 0.15767570563383954,
        Madrid: 0.2771992640023346,
        Zidane: 0.3218878635800967,
        'Florentino Perez': 0.31535141126767907,
        leave: 0.1632670522868711,
        manager: 0.12690962022792524,
        tancredipalmeri: 0.3218878635800967,
        Perez: 0.4543985280046692,
        Florentino: 0.44189852800466917
    },
    {
        Cannavaro: 0.2709492640023346,
        Ashley: 0.2771992640023346,
        'Ashley Cole': 0.15767570563383954,
        Casillas: 0.3896966806905289,
        Ronaldo: 0.22094926400233458,
        Zidane: 0.22094926400233458,
        Messi: 0.22094926400233458,
        Lampard: 0.22094926400233458,
        Iniesta: 0.22094926400233458,
        Terry: 0.2771992640023346,
        Henry: 0.19890866571173632,
        Cole: 0.22094926400233458,
        Ivanovic: 0.3218878635800967
    },
    {
        RT: 0.3396966806905289,
        effleurer: 0.22094926400233458,
        'n\'a': 0.2709492640023346,
        top: 0.13189246756926315,
        Zidane: 0.2709492640023346,
        entraineur: 0.22094926400233458,
        monde: 0.22094926400233458,
        au: 0.2271992640023346,
        'au monde': 0.20434237230050623,
        Mvssi10: 0.3218878635800967,
        JAMAIS: 0.2709492640023346
    },
    {
        RT: 0.3396966806905289,
        Real: 0.10790900513119943,
        FrenchRMCF: 0.3218878635800967,
        en: 0.2271992640023346,
        histoire: 0.2709492640023346,
        coach: 0.2271992640023346,
        au: 0.2271992640023346,
        Zidane: 0.22094926400233458,
        'en tant': 0.15767570563383954,
        tant: 0.22094926400233458
    }
]
</script>

在Javascript中合并对象并使用相同的键添加值

1 个答案: