我会创建几个日期。
library(lubridate)
x <- ymd(c("2012-03-26", "2012-05-04", "2012-09-23", "2012-12-31"))
我可以从这些x
值中提取年份和季度。
quarter(x, with_year = TRUE, fiscal_start = 10)
[1] 2012.2 2012.3 2012.4 2013.1
但我似乎无法提取只是财政年度。这不起作用,但会是什么?
year(x, with_year = TRUE, fiscal_start = 10)
我收到以下错误消息:
年份错误(x,with_year = TRUE,fiscal_start = 10): 未使用的参数(with_year = TRUE,fiscal_start = 10)
答案 0 :(得分:4)
如果你不介意另外一步,你可以提取你宿舍的前4个字符以获得这些年份。
library(lubridate)
x <- ymd(c("2012-03-26", "2012-05-04", "2012-09-23", "2012-12-31"))
q <- quarter(x, with_year = TRUE, fiscal_start = 10)
q
#> [1] 2012.2 2012.3 2012.4 2013.1
fy <- stringr::str_sub(q, 1, 4)
fy
#> [1] "2012" "2012" "2012" "2013"
答案 1 :(得分:3)
library(lubridate)
library(data.table)
fiscal_start_month = 10
x <- data.table(Dates = ymd(c("2012-03-26", "2012-05-04", "2012-09-23", "2012-12-31")))
x[, Fiscal_Year := ifelse(month(Dates) >= fiscal_start_month, year(Dates) + 1, year(Dates))]
这将产生:
Dates Fiscal_Year
1: 2012-03-26 2012
2: 2012-05-04 2012
3: 2012-09-23 2012
4: 2012-12-31 2013