我试图从跟随xml中提取errorMessage元素但是因为它似乎无法找到标记而收到错误。我有什么想法,我做错了什么?非常感谢
<order>
<orderReference>ABCD</orderReference>
<status>Error</status>
<errors>
<error>
<errorCode>1102</errorCode>
<errorMessage><![CDATA[ "Job with same reference already exists in file" ]]></errorMessage>
</error>
</errors>
foreach (XElement element in doc.Descendants("order"))
{
string value = element.Element("orderReference").Value;
string value2 = element.Element("status").Value;
string value3 = "";
if (value2 == "Error")
{
value3 = element.Element("errorMessage").Value;
}
Console.WriteLine(value + ' ' + value2 + ' ' + value3);
}
答案 0 :(得分:1)
试试这个:
value3 = element.Descendants("errorMessage").FirstOrDefault()?.Value;
答案 1 :(得分:0)
您无法直接访问子元素。你应该使用XPATH:errors / error / errorMessage
foreach (XElement element in doc.Descendants("order"))
{
string value = element.Element("orderReference").Value;
string value2 = element.Element("status").Value;
string value3 = "";
if (value2 == "Error")
{
value3 = element.Element("errors/error/errorMessage").Value;
}
Console.WriteLine(value + ' ' + value2 + ' ' + value3);
}
您也可以使用GetElementsByTagName。
value3 = doc.GetElementsByTagName("errorMessage");
它将返回包含“errorMessage”
的节点集合答案 2 :(得分:0)
对于可能遇到此问题的VB'ers
Dim xe As XElement
'to load
' xe = XElement.Load("path / URI")
'for testing
xe = <order>
<orderReference>ABCD</orderReference>
<status>Error</status>
<errors>
<error>
<errorCode>1102</errorCode>
<errorMessage><![CDATA[ "Job with same reference already exists in file" ]]></errorMessage>
</error>
</errors>
</order>
'get first
Dim errMess As String = xe...<errorMessage>.FirstOrDefault.Value
'get ALL <errorMessage> elements
Dim ie As IEnumerable(Of XElement) = xe...<errorMessage>
For Each el As XElement In ie
Debug.WriteLine(el.Value)
Next