Question

我写了一个函数，我通过了所有的params来添加用户。

 public function userAddAction()
{

    $this->requirePostParams(['username', 'usernameCanonical', 'email', 'emailCanonical', 'password', 'firstName', 'lastName', 'birthDay',
                              'addressOne', 'addressTwo', 'city', 'country', 'postCode', 'mobile', 'about']);

    $this->get('user')->addNewUser($this->data['username'], $this->data['usernameCanonical'], $this->data['email'],
                                             $this->data['password'], $this->data['emailCanonical'], $this->data['firstName'],
                                             $this->data['lastName'], $this->data['birthDay'],  $this->data['addressOne'],
                                             $this->data['addressTwo'], $this->data['city'], $this->data['country'], $this->data['postCode'],
                                             $this->data['mobile'], $this->data['about']);

    return $this->success();
}

protected function requirePostParams($params)
{
    $currentRequest = $this->get('request_stack')->getCurrentRequest();

    $postData = $currentRequest->request->all();

    $postContent = json_decode($currentRequest->getContent(), true);

    if (!empty($postContent)) {
        $postData = $postContent;
    }

    $this->data = $postData;

    $missingParams = [];

    foreach ($params as $param) {
        if (!array_key_exists($param, $postData)) {
            $missingParams[] = $param;
        }
    }

    if (!empty($missingParams)) {
        $this->terminateWithResponse($this->jsonError(sprintf("Missing params: %s", join(', ', $missingParams))));
    }
}

现在，我想将所有$ this-＆gt;数据....打包到一个调用中，以减少我需要输入的所有字段..

Answer 1

您应该可以在这里使用Symfony Forms。

通常你需要调用类似的东西：

handleRequest

但据我所知，你的请求中有json字符串。因此，在设置$this->data后，您需要拨打$form->submit($this->data);

，而不是

try
{
    using(var con = new SqlConnection(conString))
    using(var cmd = new SqlCommand("insert into adjustments_config(document_number)values(@docNumber)", con)
    {
        con.Open();
        cmd.Parameters.AddWithValue("@docNumber", TextBoxDocNo.Text);
        var rowsAffected = cmd.ExecuteNonQuery();

        // ..validate rows affected
        Response.Redirect("About.aspx");
    }
}
catch(SqlException ex)
{
    MessageBox.Show(ex.Message);
}

。

您可以查看此方法HttpFoundationRequestHandler::handleRequest，它可以帮助您更好地了解表单实际上如何与请求一起使用。

Symfony - 打包数据

1 个答案: