Question

我有python脚本有输入命令，即从用户输入（目录）。使用PyInstaller我生成了该脚本的exe。现在我想通过给出输入参数来消耗C＃中的这个exe。但不知何故，即使在从C＃发出参数之后，也没有采取并弹出Python exe命令提示符。

Python代码：

def CreateCSVFile(CSVDirectory):
    try:
        file_path = os.path.join(CSVDirectory, 'ExportResult_Stamp.csv')
        ## delete only if file exists ##
        if os.path.exists(file_path):
            os.remove(file_path)
        # Create column names as required
        row = ['FileName', 'Document123','abc','xyz','zzz']
        with open(file_path, 'w+') as csvFile:
            writer = csv.writer(csvFile)
            writer.writerow(row)
        csvFile.close()
    except Exception as e:
        print(str("Exception occurs:"+ e))

strDocDir = input("Give document directory:")
#print(strDocDir)
if os.path.exists(os.path.dirname(strDocDir)):
    CreateCSVFile(strDocDir)
else:   
    warnings.warn("Provided directory doesn't exist:" + strDocDir)

C＃代码：

string strCurrentPath = System.IO.Path.GetDirectoryName(Application.ExecutablePath);
                ProcessStartInfo startInfo = new ProcessStartInfo(string.Concat(strCurrentPath, "\\Test\\", "CSV.exe"));
                startInfo.Arguments = @"C:\Pankaj\Office\ML\Projects\Stampdocuments\DDR041";
                startInfo.UseShellExecute = true;                
                var process = System.Diagnostics.Process.Start(startInfo);
                process.WaitForExit();

请建议。

Answer 1

import sys

.....

strDocDir = sys.argv[1]

改变它是因为你传递的参数没有输入任何东西，如果你想使用输入仍然你应该检查出Repeatably Feeding Input to a Process' Standard Input（答案是因为新行还需要python）

 var process = new Process
                          {
                              StartInfo =
                                  {
                                      FileName = string.Concat(strCurrentPath, "\\Test\\", "CSV.exe"),
                                      RedirectStandardInput = true,
                                      RedirectStandardError = true,
                                      RedirectStandardOutput = true,
                                      UseShellExecute = false,
                                      CreateNoWindow = true,
                                      ErrorDialog = false
                                  }
                          };


        process.EnableRaisingEvents = false;

        process.Start();

        var standardInput = process.StandardInput;
        standardInput.AutoFlush = true;
        var standardOutput = process.StandardOutput;
        var standardError = process.StandardError;

        standardInput.Write(@"C:\Pankaj\Office\ML\Projects\Stampdocuments\DDR041");
        standardInput.Close(); // <-- output doesn't arrive before after this line
        var outputData = standardOutput.ReadLine();

        process.Close();
        process.Dispose();

顺便说一下我对c＃的Process模块一无所知，所以我只是为你的代码复制和编辑了

运行python脚本（具有input（））exe形式C＃

1 个答案: