Question

这是json

 [
  {
    "SUBTASK": {
      "id": 10,
      "name": "TestMap",
      "description": "",
      "version":"1.0"
    }
  },
  {
    "SUBTASK": {
      "id": 23,
      "name": "TestMap",
      "description": "",
      "version":"2.0"
    }
  },
  {
    "SUBTASK": {
      "id": 12,
      "name": "Tree",
      "description": "",
      "version":"13.0"
    }
  },
  {
    "SUBTASK": {
      "id": 32,
      "name": "Tree",
      "description": "",
      "version":"10.0"
    }
  }
]

需要获得SUBTASKS的最新数量即。过滤最新版本的SUBTASK并尊重名称。

所以最终的json会像：

final:[{"SUBTASK":{"id":12.0,"name":"Tree","description":"","version":"13.0"}},{"SUBTASK":{"id":23.0,"name":"TestMap","description":"","version":"2.0"}}]

我使用下面的java代码：

Java Snippet

   public void getLatest(String json) throws Exception {
        // converting json to java Object
        List<Map<String, Object>> taskList = new Gson().fromJson(json, new TypeToken<List<Map<String, Object>>>() {
        }.getType());

        Map<String, Object> taskVersionedMap = new HashMap<String, Object>();

        for (int i = 0; i < taskList.size(); i++) {
            Map<String, Object> processMap = taskList.get(i);
            Map<String, Object> process = (Map<String, Object>) processMap.get("SUBTASK");

            String process_name = process.get("name").toString() + "_" + process.get("version");
            taskVersionedMap.put(process_name, processMap);

            for (Map.Entry<String, Object> entry : taskVersionedMap.entrySet()) {
                String[] split = entry.getKey().split("_");
                double version = Double.parseDouble(split[1]);
                String name = split[0];
                for (Map.Entry<String, Object> entry2 : taskVersionedMap.entrySet()) {
                    String[] split_2 = entry2.getKey().split("_");
                    double version_2 = Double.parseDouble(split_2[1]);
                    String name_2 = split_2[0];
                    if (name.equals(name_2)) {
                        if (version < version_2) {
                            String removedProcessName = name + "_" + version;
                            taskVersionedMap.put(removedProcessName, "ignored");
                        }
                    }
                }

            }
        }
        List<Map<String, Object>> filteredVersionList = new ArrayList<Map<String, Object>>();
        for (Map.Entry<String, Object> mapValues : taskVersionedMap.entrySet()) {
            if (!mapValues.getValue().toString().equals("ignored")) {
                try {
                    filteredVersionList.add((Map<String, Object>) mapValues.getValue());
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        }
        System.out.println("final:"+new Gson().toJson(filteredVersionList));

    }

上述代码可以提供准确的结果并且非常耗时。

但可以优化代码 因为正在处理的真实数据json将非常强大近500个子任务

获取有关java

0 个答案: