Question

我正在编辑存储过程以获取距离并从中对其进行排序。我正在使用的查询正在处理另一个存储过程。

    SELECT  *,


( 
    ACOS( COS( RADIANS( 41.993000000  ) ) 
          * COS( RADIANS( u.real_users_lat ) )
          * COS( RADIANS( u.real_users_long ) - RADIANS( -87.696207000 ) )
          + SIN( RADIANS( 41.993000000  ) )
          * SIN( RADIANS( u.real_users_lat ) )
      )
    * 6371
    ) AS distance_in_km

FROM products
LEFT JOIN users u on u.id = products.created_by
LEFT JOIN product_categories on product_categories.product_id = products.id
WHERE products.starting_bid <= @price and product_categories.category_id = @category_id
ORDER BY 
     CASE WHEN @sort_direction = 'asc' THEN products.date_created END asc,
     CASE WHEN @sort_direction = 'desc' THEN products.date_created END desc,
    CASE WHEN @sort_distance = 'nearest' THEN distance_in_km END desc,
    CASE WHEN @sort_distance = 'farthest' THEN distance_in_km END asc

END

错误是Invalid column name 'distance_in_km'.，但在我的其他存储过程中，它正在运行。

SELECT 
    distinct Products.*, 
    (
        SELECT Count(bids.id) 
        FROM bids
        Where bids.product_id = products.id
    ) as bid_count ,
    (
    SELECT firebase_user_id
    FROM Users
    Where Users.id = created_by
    ) as seller_firebase_id , 
    ( 
    ACOS( COS( RADIANS( 41.993000000  ) ) 
          * COS( RADIANS( u.real_users_lat ) )
          * COS( RADIANS( u.real_users_long ) - RADIANS( -87.696207000 ) )
          + SIN( RADIANS( 41.993000000  ) )
          * SIN( RADIANS( u.real_users_lat ) )
      )
    * 6371
    ) AS distance_in_km


FROM Products
LEFT JOIN areas on areas.id = products.area
LEFT JOIN Product_categories on Product_categories.product_id = products.id
LEFT JOIN Users u on u.id = Products.created_by 
WHERE products.status <> 4 
ORDER BY distance_in_km DESC


END

请让我知道我做错了什么。

Answer 1

你没有做错任何事。 SQL服务器根本不允许以这种方式使用别名列。直的WHERE没问题，但你不能在表达式中使用它们。

不要问我为什么！

如果您需要这样做，那么将您的SELECT语句包装在CTE或内联视图中，它将正常工作。

最后还有一个额外的END;或许这只是问题的复制和粘贴问题。

这应该使用内联视图

关闭

SELECT  *,distance_in_km
FROM products
LEFT JOIN 
(select *, ( 
    ACOS( COS( RADIANS( 41.993000000  ) ) 
          * COS( RADIANS( u.real_users_lat ) )
          * COS( RADIANS( u.real_users_long ) - RADIANS( -87.696207000 ) )
          + SIN( RADIANS( 41.993000000  ) )
          * SIN( RADIANS( u.real_users_lat ) )
      )
    * 6371
    ) AS distance_in_km
from users) u on u.id = products.created_by
LEFT JOIN product_categories on product_categories.product_id = products.id
WHERE products.starting_bid <= @price and product_categories.category_id = @category_id
ORDER BY 
     CASE WHEN @sort_direction = 'asc' THEN products.date_created END asc,
     CASE WHEN @sort_direction = 'desc' THEN products.date_created END desc,
    CASE WHEN @sort_distance = 'nearest' THEN distance_in_km END desc,
    CASE WHEN @sort_distance = 'farthest' THEN distance_in_km END asc

Eralper的答案显示了CTE的一般技术。

Answer 2

Jovin，你不能直接在它创建的SQL中使用计算列

我的意思是，以下将不起作用

declare @sort varchar(5) = 'desc'
select [name], trim([name]) as tname
from sys.tables
order by 
    case when @sort = 'desc' then tname end desc,
    case when @sort = 'asc' then tname end asc

您可以执行以下某项操作

declare @sort varchar(5) = 'desc'
select [name], trim([name]) as tname
from sys.tables
order by 
    case when @sort = 'desc' then trim([name]) end desc,
    case when @sort = 'asc' then trim([name]) end asc

或者只使用SQL CTE表达式

declare @sort varchar(5) = 'desc'
;with cte as (
    select [name], trim([name]) as tname
    from sys.tables
) 
select *
from cte
order by 
    case when @sort = 'desc' then tname end desc,
    case when @sort = 'asc' then tname end asc

无法识别SQL作为关键字

2 个答案: