Question

我在我的系统中成功使用了和弦。但是，现在我有一个案例，我必须按顺序运行和弦数量（第二个在第一个结束时开始）。所以，我试图使用和弦链。但它对我不起作用。

@app.task(bind=True)
def some_celery_beat_worker(self):
    feed_chain = []
    for feed in feed_list:
        celery_task_list = [perform single_task.si(url)
                                for url in some_url_list]
        per_feed_chord = chord(celery_task_list, chord_callback.si(feed['_id'], feed['xml_file_name']))
        feed_chain.append(per_feed_chord)
    chain(*feed_chain).delay()

将此作为追溯：

Traceback (most recent call last):
  File "python3.4/site-packages/celery/app/trace.py", line 374, in trace_task
    R = retval = fun(*args, **kwargs)
  File "python3.4/site-packages/celery/app/trace.py", line 629, in __protected_call__
    return self.run(*args, **kwargs)
  File "workers.py", line 156, in joblist_updater_worker
    chain(*feed_chain).delay()
  File "python3.4/site-packages/celery/canvas.py", line 182, in delay
    return self.apply_async(partial_args, partial_kwargs)
  File "/python3.4/site-packages/celery/canvas.py", line 566, in apply_async
    dict(self.options, **options) if options else self.options))
  File "python3.4/site-packages/celery/canvas.py", line 596, in run
    first_task.apply_async(**options)
  File "python3.4/site-packages/celery/canvas.py", line 1241, in apply_async
    return (self.tasks[0] | body).set(task_id=task_id).apply_async(
KeyError: 0

我需要的是修复这个特定的工作流程，或任何可以解决这个特殊问题的替代工作流程（一个接一个地运行和弦数量）

Answer 1

问题在于我如何形成chain。这不是正确的（至少对于我的芹菜版本），尽管在很多地方都有建议。

适用于我的方法。

feed_chain = chain()
for feed in feed_list:
    feed_chain |= chord(args)

feed_chain.delay()

如何在芹菜中成功运行弦和弦？

1 个答案: