Question

我正在尝试使用以下PHP代码向Google Places API发送帖子请求但我收到错误

string（141）＆＃34; {＆＃34; error_message＆＃34; ：＆＃34;此服务需要API密钥。＆＃34;，＆＃34; html_attributions＆＃34; ：[]，＆＃34;结果＆＃34; ：[]，＆＃34;状态＆＃34; ：＆＃34; REQUEST_DENIED＆＃34; }＆＃34;

<?php
include_once 'configuration.php';

$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json';
$data = array('query' => 'restaurants in Sydney', 'key' => API_KEY);

$options = array(
    'http' => array(
        'header'  => "Content-type: application/x-www-form-urlencoded\r\n",
        'method'  => 'POST',
        'content' => http_build_query($data)
    )
);
$context  = stream_context_create($options);
$result = file_get_contents($url, false, $context);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

问题出在哪里？

Answer 1

如documentation of text search中所述，参数需要在GET方法中。您以POST方式提供了它。

A Text Search request is an HTTP URL of the following form:

    https://maps.googleapis.com/maps/api/place/textsearch/output?parameters

...

Certain parameters are required to initiate a search request. As is standard in URLs, all parameters are separated using the ampersand (&) character.

请尝试使用此代码段：

<?php
include_once 'configuration.php';

$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?query=' . urlencode('restaurants in Sydney') . '&key=' . API_KEY;

$result = file_get_contents($url);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

要使用数组参数，请将$url更改为：

$data = array('query' => 'restaurants in Sydney', 'key' => API_KEY);
$url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?' . http_build_query($data);

为什么我会收到错误＆＃34;此服务需要API密钥＆＃34;？

1 个答案: