Question

我正在实施一项游戏，允许两名玩家从一堆27支球队中交替选择。每个球员每回合可以拿1,2或3支球;球员被迫拿走最后一棒。

我已经完成了大部分代码，但我必须包含验证。除了1-3支球队外，球员不允许拿最后一根棍子。我尝试过使用continue语句，但当玩家2超过限制时，程序将返回到玩家1。

这是我到目前为止所拥有的：

count = 27
T = False
F = False

while count > 1:

  Playerone = int(input("Player 1's Turn, Enter from 1-3"))
  if Playerone < 1 or Playerone > 3:
    print("Error")
    continue
  count -= Playerone
  print(count)

  if count == 1:
    print("P1 wins")
    break

  if count < 1:
    print("You can't pick up those many sticks")
    continue

  Playertwo = int(input("Player 2's Turn, Enter from 1-3"))
  if Playertwo < 1 or Playertwo > 3:
    print("Error")
    continue

  count -= Playertwo
  print(count)

  if count == 1:
    print("P2 wins")
    break

  if count < 1:
    print("You can't pick up those many sticks")
    continue

最后一个if语句是问题

非常感谢帮助，

Answer 1

你的循环流程存在一个基本缺陷：无论播放器输入遇到什么问题，你都可以使用continue返回循环顶部，这会让你回到播放器1你需要解决这个问题：循环播放给定玩家的输入，直到它在所有方面都有效。这样的事情应该做：

valid = False
while not valid:
  Playertwo = int(input("Player 2's Turn, Enter from 1-3"))

  if Playertwo < 1 or Playertwo > 3:
    print("Error")

  elif count - Playertwo < 1:
    print("You can't pick up those many sticks")

  else:
    valid = True

将此应用于每位玩家的输入。一旦你离开这个循环，你就有了有效的输入。从那里，您可以减少计数并确定某人是否赢了。

Answer 2

确保有效用户输入的一种方法是使用循环。

以下是您可能使用的功能的快速示例：

def prompt_integer(msg, minval, maxval, err_invalid, err_oob):
    while True:
        resp = input(msg) # Python3, use raw_input in Python2
        try:
            resp = int(resp)
            if minval <= resp <= maxval:
                return resp
            else:
                print(err_oob)
        except ValueError:
            print(err_invalid)


x = prompt_integer("Enter an integer: ", 1, 3, "Invalid Integer.", "Integer Out of Bounds")

此处，在用户输入1到3（含）之间的有效整数之前，函数不会返回。

如果他们输入＆＃39; abc＆＃39;，程序将显示＆＃34;无效的整数。＆＃34;并再次问他们。

如果他们输入，比如5，当你指定边界是1和3时，程序将显示＆＃34;整数超出边界＆＃34;，然后再次询问他们。

当此功能返回时，您知道您已获得可接受的值。

您可以在代码中使用此功能，并在每次调用maxval参数时根据他们能够拾取的数量来修改。

Answer 3

这就是我要做的事情，你可能会对Classes发疯，但现在对你来说有点太多了（但有些事情需要研究）。您还应该研究创建方法，但请查看下面的代码和我留下的评论。

def player_input(player_number: int):  # This is a method, that requires an integer to be pass to it
    p_input = int(input("Player {}'s Turn, Enter from 1-3: ".format(player_number)))
    while p_input < 1 or p_input > 3:  # This will cause a loop continuously asking the player to input a number until that number is between 1 or 3. 
        print('Please choose a number between 1 and 3')
        p_input = int(input("Player {}'s Turn, Enter from 1-3: ".format(player_number)))  # Format will replace the '{}' with the value of the variable you give it
    return p_input  # This 'return' line will return the what the results of what the player typed in


def found_winner(stick_number: int):  # stick_number is a required variable and ': int' requires that that variable be an integer
    winner = False
    if stick_number == 1:
        winner = True
    return winner  # This method will return if a winner is found or not


def next_player(player_number: int):  # This method will swap the players turn
    if player_number == 1:
        player_number = 2
    elif player_number == 2:
        player_number = 1
    return player_number


def start_game(stick_count: int = 27):  # This method will start the game, the '= 27' says that you can give me any stick count you want(that is an integer), but if you don't provide one I will use '27' by default
    player_number = 1
    while stick_count > 1:  # This will loop through until the stick count is 1 or less
        sticks_to_remove = player_input(player_number)  # I store the plays result just in case the stick_count goes below 1, and then I remove the sticks if the the count doesn't go below 1
        if stick_count - sticks_to_remove < 1:
            print('You cant pick up that many sticks')
            continue
        else:
            stick_count -= sticks_to_remove  # Remove the sticks
        if found_winner(stick_count):  # Look for the winner
            print('Player {} wins!'.format(player_number))
        else:
            player_number = next_player(player_number)  # If no winner go to the next player


if __name__ == '__main__':  # This says only execute the 'start_game()' method automatically if this python script is called, this is useful later when you start creating more complicated Python scripts that span multiple files.
    start_game()

如何在if语句后清除变量？

3 个答案: