我试图在新的导航组件中找到一个方法,但我没有找到任何相关信息。
我目前的目的地是:
mainHostFragment.findNavController().currentDestination
但我无法参考显示的片段。
答案 0 :(得分:9)
导航不提供任何获取当前目的地实现的机制(即片段本身)。
根据Creating event callbacks to the activity,你应该通过
与你的片段进行交流onAttach
方法中注册回调,将您的Activity转换为您提供的接口的实例ViewModel
。答案 1 :(得分:9)
您可以执行以下操作:
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
val navHostFragment = supportFragmentManager.fragments.first() as? NavHostFragment
if(navHostFragment != null) {
val childFragments = navHostFragment.childFragmentManager.fragments
childFragments.forEach { fragment ->
fragment.onActivityResult(requestCode, resultCode, data)
}
}
}
但要进行更高级的通信,在 Fragment.onAttach()(Fragment -> Activity rather one direction communication
)和 SharedViewModel ( bidirectional
,对于拥有ViewModelProviders, and Lifecycle owner that is scoped to getActivity()
来说很重要)
答案 2 :(得分:2)
@Override 公共无效onBackPressed(){ super.onBackPressed();
NavController navController = Navigation.findNavController(this, R.id.fragment);
int id=navController.getCurrentDestination().getId();
if(id==R.id.startGameFragment ){
selectedPosition(0);
}else if(id==R.id.gameFragment ){
selectedPosition(1);
}else if(id==R.id.endGameFragment ){
selectedPosition(2);
}
}enter code here
private void selectedPosition(int pos){
for (int i = 0; i >=nav_view.getMenu().size(); i++) {
nav_view.getMenu().getItem(pos).setChecked(false);
}
nav_view.getMenu().getItem(pos).setChecked(true);
}
答案 3 :(得分:1)
从具有NavHostFragment的Activity中,下面的代码片段可用于检索Active Fragment的实例。
kotlin
val currentFragment = mNavHostFragment?.childFragmentManager?.primaryNavigationFragment
java
Fragment navHostFragment = getSupportFragmentManager().getPrimaryNavigationFragment();
Fragment currentFragment = navHostFragment.getChildFragmentManager().getFragments().get(0);
答案 4 :(得分:0)
使用Michal的答案,我编写了此扩展功能进行测试:
@Suppress("UNCHECKED_CAST")
fun <F : Fragment> AppCompatActivity.getFragment(fragmentClass: Class<F>): F? {
val navHostFragment = this.supportFragmentManager.fragments.first() as NavHostFragment
navHostFragment.childFragmentManager.fragments.forEach {
if (fragmentClass.isAssignableFrom(it.javaClass)) {
return it as F
}
}
return null
}
像这样使用:
val myFragment = activity.getFragment(MyFragment::class.java)
答案 5 :(得分:0)
参考显示的片段(AndroidX):
public Fragment getForegroundFragment(){
Fragment navHostFragment = getSupportFragmentManager().findFragmentById(R.id.nav_host_fragment);
return navHostFragment == null ? null : navHostFragment.getChildFragmentManager().getFragments().get(0);
}
nav_host_fragment
是一个ID
fragment
中的activity_main.xml
标签中的android:name="androidx.navigation.fragment.NavHostFragment"
标签中的一个
答案 6 :(得分:0)
基于其他答案
Fragment navHostFragment = getSupportFragmentManager().getPrimaryNavigationFragment();
Fragment fragment = navHostFragment.getChildFragmentManager().getFragments().get(0);
((Your Fragment Class) fragment).(public method inside the fragment)
为我工作
答案 7 :(得分:0)
我用androidx发布了完整的答案。 护理:在我的情况下,我需要检索一个子片段(不能是第一个)。
在 MainActivity 中,您应该有类似的内容:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
DrawerLayout drawer = findViewById(R.id.drawer_layout);
NavigationView navigationView = findViewById(R.id.nav_view);
// Passing each menu ID as a set of Ids because each
// menu should be considered as top level destinations.
mAppBarConfiguration = new AppBarConfiguration.Builder(
R.id.mytest, R.id.nav_help)
.setDrawerLayout(drawer)
.build();
NavController navController = Navigation.findNavController(this, R.id.nav_host_fragment);
NavigationUI.setupActionBarWithNavController(this, navController, mAppBarConfiguration);
NavigationUI.setupWithNavController(navigationView, navController);
...
然后,您必须创建一种方法来检索好的片段。
private MyTestFragment getMyTestFragment(){
MyTestFragment resultFragment = null;
Fragment navHostFragment = getSupportFragmentManager().findFragmentById(R.id.nav_host_fragment);
if(navHostFragment != null && navHostFragment.getChildFragmentManager() != null) {
List<Fragment> fragmentList = navHostFragment.getChildFragmentManager().getFragments();
for (Fragment fragment : fragmentList) {
if (fragment instanceof MyTest) {
resultFragment = (MyTest) fragment;
break;
}
}
}
return resultFragment;
}
最后,你明白了。
答案 8 :(得分:0)
真的来处理这个最好的和正确的方式是使用一个接口。视图模型应该真正用于在活动和片段之间传递数据。这是我如何解决了这个问题:
创建接口
interface NavigationInterface {
fun referenceCourseListFragment(fragment: CourseListFragment)
fun referenceCouseDetailFragment(fragment: CourseDetailInfoFragment)
}
确认活动工具接口
class NotesActivity : AppCompatActivity(), NavigationInterface {}
请一定要为每个需要引用,然后片段lateinit VAR
private lateinit var courseListFragment: CourseListFragment
private lateinit var courseDetailInfoFragment: CourseDetailInfoFragment
现在在onCreateView方法中的每个片段,以确保创建接口侦听和与接口回传的片段
private lateinit var navigationInterface: NavigationInterface
override fun onCreateView(
inflater: LayoutInflater, container: ViewGroup?,
savedInstanceState: Bundle?
): View? {
//establish interface communication
activity?.let {
instantiateNavigationInterface(it)
}
// Inflate the layout for this fragment
fragmentView = inflater.inflate(R.layout.fragment_course_list, container,
false)
navigationInterface.referenceCourseListFragment(this)
return fragmentView
}
现在回到活动中,你应该能够通过接口回调
来实例片段对象以供参考override fun referenceCourseListFragment(fragment: CourseListFragment) {
courseListFragment = fragment
}
override fun referenceCouseDetailFragment(fragment: CourseDetailInfoFragment)
{
courseDetailInfoFragment = fragment
}
答案 9 :(得分:0)
我认为存在异常的可能性,因此您可以使用接口回调,这是一种从一端到另一端进行通信的可靠方式,仅通过代码下方的引用检查。
<块引用>Fragment A(){ interface ClickPostItemListener { 有趣的点击(位置:Int) }
val itemListener = object : ClickPostItemListener{
override fun onClicked(position: Int) {
postBackNForth(position)
}
} } Fragment B(clickItem:ClickPostItemListener ){ clickItem() }