Question

所以我有这个控制器：

@RequestMapping(value = "/zone/settings/ranged/update", method = RequestMethod.POST, produces="application/json", consumes="application/json")
public @ResponseBody ResponseEntity<Map<String, Object>> zoneSettingsRangedUpdate(
        WebRequest request,
        @RequestBody RoundRangeData data,
        Map<String, Object> model
) throws IOException {
    model.put("request", data);
    model.put("success",true);

    return new ResponseEntity<>(model, HttpStatus.OK);
}

以此作为POJO：

public class RoundRangeData {
    private BigInteger pricingDate;
    private Long zoneid;
    private Long psid;
    private Float roundTo;
    private Float lowerLimit;
    private Float upperLimit;

public RoundRangeData() {

}

public RoundRangeData(BigInteger pricingDate, Long zoneid, Long psid, Float roundTo, Float lowerLimit, Float upperLimit) {
    this.pricingDate = pricingDate;
    this.zoneid = zoneid;
    this.psid = psid;
    this.roundTo = roundTo;
    this.lowerLimit = lowerLimit;
    this.upperLimit = upperLimit;
}

public BigInteger getPricingDate() {
    return pricingDate;
}

public void setPricingDate(BigInteger pricingDate) {
    this.pricingDate = pricingDate;
}

public Long getZoneid() {
    return zoneid;
}

public void setZoneid(Long zoneId) {
    this.zoneid = zoneId;
}

public Long getPsid() {
    return psid;
}

public void setPsid(Long psid) {
    this.psid = psid;
}

public Float getRoundTo() {
    return roundTo;
}

public void setRoundTo(Float roundTo) {
    this.roundTo = roundTo;
}

public Float getLowerLimit() {
    return lowerLimit;
}

public void setLowerLimit(Float lowerLimit) {
    this.lowerLimit = lowerLimit;
}

public Float getUpperLimit() {
    return upperLimit;
}

public void setUpperLimit(Float upperLimit) {
    this.upperLimit = upperLimit;
}
}

使用此请求（Chrome devtools屏幕截图，实际请求引用了属性）：

我一直收到这个错误：

警告：无法写入HTTP消息：org.springframework.http.converter.HttpMessageNotWritableException：无法写入内容：没有找到序列化程序，用于类org.springframework.validation.DefaultMessageCodesResolver并且没有发现任何属性创建BeanSerializer（以避免异常，禁用SerializationFeature.FAIL_ON_EMPTY_BEANS）（通过引用链：org.springframework.validation.support.BindingAwareModelMap [＆＃34; org.springframework.validation.BindingResult.roundRangeData＆＃34;] - ＆gt; org.springframework .validation.BeanPropertyBindingResult [＆＃34; MessageCodesResolver的信息＆＃34;]）;嵌套异常是com.fasterxml.jackson.databind.JsonMappingException：没有为类org.springframework.validation.DefaultMessageCodesResolver找到序列化器，也没有发现创建BeanSerializer的属性（为了避免异常，禁用SerializationFeature.FAIL_ON_EMPTY_BEANS）（通过引用链：org.springframework .validation.support.BindingAwareModelMap [＆＃34; org.springframework.validation.BindingResult.roundRangeData＆＃34;] - ＆GT; org.springframework.validation.BeanPropertyBindingResult [＆＃34; MessageCodesResolver的信息＆＃34;]）

我尝试过：

将字段访问者更改为公开
尝试消化正常字符串，同样的错误
使用@JSONProperty
创建了一个单元测试，并使用生成的JSON调用控制器来自RoundRangeData对象实例的对象映射器

将Java对象序列化为JSON适用于响应，但我有没有运气将JSON序列化到我控制器中的Java对象中。

Answer 1

您需要从参数列表中删除属性model。问题是如果你为杰克逊启用FAIL_ON_EMPTY_BEANS，你会得到一个包含大量信息的巨大回复，我相信你不需要这些信息。

我会在新的ResponseEntity中返回其他内容，比如创建自己的地图，如果这是你的愿望。

Answer 2

试试这个。

public class MapSerializer extends JsonSerializer<SpecialMap> {
    @Override
    public void serialize(SpecialMap map, JsonGenerator jgen,
                          SerializerProvider provider) throws IOException,
            JsonProcessingException {
        jgen.writeStartObject();
        for (String key : map.keySet()) {
            jgen.writeStringField(key, map.get(key));
        }
        jgen.writeEndObject();
    }
}


public class SpecialMap extends HashMap<String,String> {
}


@RequestMapping(value = "/zone/settings/ranged/update", method = {RequestMethod.POST}, produces = MediaType.APPLICATION_JSON_VALUE, consumes = MediaType.APPLICATION_JSON_VALUE)
    public ResponseEntity<Map<String, Object>> zoneSettingsRangedUpdate(
            @RequestBody RoundRangeData data
    ) throws IOException {

        Map<String, Object> model = new HashMap<>();
        ObjectMapper mapper = new ObjectMapper();

        SimpleModule module = new SimpleModule();
        module.addSerializer(SpecialMap.class, new MapSerializer());
        mapper.registerModule(module);

        String serialized = mapper.writeValueAsString(data);
       // return serialized;
        model.put("request", serialized);
        model.put("success",true);

        return new ResponseEntity<Map<String, Object>>(model, HttpStatus.OK);
    }

查看成功回复的图像。

Answer 3

您只需要在pojo中实现Serializble

public class RoundRangeData implements Serializable {
    //code
}

Spring Post Controller未将JSON请求序列化为Java对象

3 个答案: