我正在开发一个我打算用于HL7消息验证的Java端点。我有一个运行的基本应用程序,它使用标准HAPI HL7验证示例的变体。如果我传递了有效的信息,我会得到"成功"响应。如果我传递了无效的消息,我仍然会得到一个"成功"响应。
我得到错误响应的唯一方法是HL7格式错误并且PipeParser抛出异常。在这种情况下,它会被捕获阻塞。
我想看到的是,如果我传入一条无效的消息,它实际上已经验证并返回所有验证错误。但我实际上并没有看到任何验证。它解析或崩溃试图解析。
我在这里缺少什么?
HapiContext context = new DefaultHapiContext();
ValidationContext validationContext = ValidationContextFactory.defaultValidation();
context.setValidationContext(validationContext);
try
{
context.getParserConfiguration().setUnexpectedSegmentBehaviour(UnexpectedSegmentBehaviourEnum.THROW_HL7_EXCEPTION);
Message messageValidationResults = context.getPipeParser().parse(hl7Message);
SimpleValidationExceptionHandler handler = new SimpleValidationExceptionHandler(context);
handler.setMinimumSeverityToCollect(Severity.INFO);
Validator<Boolean> validator = context.getMessageValidator();
if (!validator.validate(messageValidationResults, handler))
{
if (handler.getExceptions().size() == 0)
{
hl7ValidationResult = "SUCCESS - Message Validated Successfully";
}
else
{
hl7ValidationResult = "ERROR - Found " + handler.getExceptions().size() + " problems\n\n";
for (Exception e : handler.getExceptions())
{
hl7ValidationResult += (e.getClass().getSimpleName() + " - " + e.getMessage()) + "\n";
}
}
}
}
catch (Exception e)
{
hl7ValidationResult = "ERROR - " + e.getMessage();
StringWriter sw = new StringWriter();
PrintWriter pw = new PrintWriter(sw);
e.printStackTrace(pw);
String sStackTrace = sw.toString();
hl7ValidationResult += "\n\n" + sStackTrace;
}
答案 0 :(得分:1)
如果您认为不正确,请忽略答案,我停止使用HL7,但是,看看我的旧项目,我找到了这个,也许它可以帮助您找到问题的解决方案:
{
DefaultValidationBuilder builder = new DefaultValidationBuilder() {
private static final long serialVersionUID = 1L;
@Override
protected void configure() {
super.configure();
forVersion(Version.V26);
}
};
HapiContext context = new DefaultHapiContext();
context.setValidationRuleBuilder(builder);
PipeParser hapiParser = context.getPipeParser();
try {
hapiParser.parse(hl7Message);
} catch (ca.uhn.hl7v2.HL7Exception e) {
// String error, String language, String requisitionNumber, String controlId, String processinId, String senderApplication, String senderFacility
errors.add(new HL7ValidationError(
"HAPI Validator error found: " + e.getMessage(),
extractor.accessPatientDirectly().getLanguage(),
extractor.accessPatientDirectly().getRequisitionNumber(),
extractor.accessPatientDirectly().getControlID(),
"",
extractor.accessPatientDirectly().getSenderApplication(),
extractor.accessPatientDirectly().getSenderFacility())
);
log.debug("HAPI Validator error found: " + e.getMessage());
}
try {
context.close();
}
catch (Exception ex) {
log.debug("Unable to close HapiContext(): " + ex.getMessage());
}
}
基本上我使用 hapiParser.parse(hl7Message); 并捕获HL7Exception