您好我有一个结构表,其中包含companies_id(PK)和parent_companies_id(FK)列以及包含companies_id(FK)和people_id(PK)的人员表。有些人可能在不同的公司。想知道包括小孩在内的各公司的数量。
+------------------+-------------------------+
| companies_id(PK) | parent_companies_id(FK) |
+------------------+-------------------------+
| 101 | null |
| 102 | 101 |
| 103 | 101 |
| 104 | 103 |
| 105 | 103 |
| 106 | 104 |
+------------------+-------------------------+
+---------------+------------------+
| people_id(PK) | companies_id(FK) |
+---------------+------------------+
| 001 | 101 |
| 002 | 102 |
| 003 | 102 |
| 004 | 104 |
| 005 | 105 |
| 006 | 106 |
+---------------+------------------+
CREATE TABLE COMPANY
( Company_ID Integer,
Parent_ID Integer
);
CREATE TABLE PEOPLE
( People_ID VARCHAR(3),
Company_ID Integer
);
INSERT INTO COMPANY VALUES (101,NULL);
INSERT INTO COMPANY VALUES (102,101);
INSERT INTO COMPANY VALUES (103,101);
INSERT INTO COMPANY VALUES (104,103);
INSERT INTO COMPANY VALUES (105,103);
INSERT INTO COMPANY VALUES (106,104);
INSERT INTO PEOPLE VALUES ('001',101);
INSERT INTO PEOPLE VALUES ('002',102);
INSERT INTO PEOPLE VALUES ('003',102);
INSERT INTO PEOPLE VALUES ('004',104);
INSERT INTO PEOPLE VALUES ('005',105);
INSERT INTO PEOPLE VALUES ('006',106);
结果必须是下一个
+--------------+------------+
| companies_id | people_qnt |
+--------------+------------+
| 101 | 6 |
| 102 | 2 |
| 103 | 3 |
| 104 | 2 |
| 105 | 1 |
| 106 | 1 |
+--------------+------------+
答案 0 :(得分:0)
我在这里假设您的var url = 'https://labs.bible.org/api/?
passage=random&type=json&callback=myCallBackFcn';
var ourRequest = new XMLHttpRequest();
ourRequest.open('GET', url);
ourRequest.onload = function(){
console.log(ourRequest.responseText);
};
ourRequest.send();
表(我称之为#34; struct")对每家公司都有一行。如果这不是真的,你应该为驾驶表使用不同的东西。
structure