我知道这涉及一个循环。我已经完成了很多搜索,但无法弄清楚。
我使用以下代码输出每行3项的数据。我真正想知道如何做的是让它们按列而不是按行升序,但动态地取决于查询中的记录数,而不是定义列中的行数。
<?php
define('DB_SERVER', "xxx");
define('DB_USER', "xxx");
define('DB_PASSWORD', "xxx");
define('DB_TABLE', "xxx");
$row_count = 0;
// The procedural way
$mysqli = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_TABLE);
$mysqli->set_charset("utf8");
$mysqli->query("SET NAMES 'utf8'");
if (mysqli_connect_errno($mysqli)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$query = "
SELECT lvm.luchtvaartmaatschappij, COUNT(*) AS CountLVMPhotos
FROM tbl_photos p
LEFT JOIN tbl_luchtvaartmaatschappij lvm
ON p.img_lvm = lvm.IATACode
WHERE p.img_creator IN ('Daniël E. Cronk','Daniel E. Cronk')
GROUP BY lvm.luchtvaartmaatschappij
ORDER BY lvm.luchtvaartmaatschappij ASC ";
$result = mysqli_query($mysqli, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($mysqli), E_USER_ERROR);
echo "
<table id='fotosBij' class='tablesorter-dropbox table-responsive ui-table-reflow'>";
echo "<tbody>";
if($result) {
while($row = mysqli_fetch_assoc($result)) {
$items_in_row = 3 ;
$index = 0 ;
echo '<tr >';
while($row = mysqli_fetch_assoc($result)){
$index++ ;
echo "<td width='250px' valign='top'>" . $row['luchtvaartmaatschappij'] . "</td>";
echo "<td width='50px' valign='top'>" . $row['CountLVMPhotos'] . "</td>";
echo "<td width='80px'> </td>";
if ($index%$items_in_row == 0){
echo "</tr>";
}
}
echo "</tbody>";
echo "</table>";
}
}
mysqli_close($mysqli);
?>
答案 0 :(得分:0)
如果我理解你想要什么,这样就可以了:
if($result) {
$row1html = "<tr>";
$row2html = "<tr>";
while($row = mysqli_fetch_assoc($result)) {
$row1html .= "<td width='250px' valign='top'>".
$row['luchtvaartmaatschappij'] ."</td>";
$row2html .= "<td width='50px' valign='top'>".
$row['CountLVMPhotos'] . "</td>";
}
$row1html = "</tr>";
$row2html = "</tr>";
echo $row1html . $row2html;
}
可能有更优雅的方式,但这应该有用。
如果你有很多数据,那么这个表格会变得很宽,所以希望你有一个设计。