Python:Decorator Dispatcher:Catch-22

时间:2018-06-04 15:02:40

标签: python python-decorators dispatch

我正在尝试构建一个基于装饰器的调度程序,例如Flask或Pyramid使用的调度程序。我得到了一些有效的东西,但遇到了一些问题22。以下代码有效,但仅限于执行foo()并设置.mq_path属性。在启动应用程序并构建可分派功能列表时,尚未设置任何属性。我想执行由事件驱动的foo()。

我可以"手动"准备一个函数列表并在我添加函数时更新,但我喜欢Flask的工作方式,只需将一个装饰器添加到一个处理URL的函数(或者在这种情况下是一个MQ路径)。

list_of_paths = []
path_dispatcher = {}

def handle_mq(path):
    def decorator(fn):
        def decorated(*args,**kwargs):
            decorated.mq_path = path
            print "Hello from the handle_mq() decorator, your path is: {0}".format(path)
            return fn(*args,**kwargs)
        return decorated
    return decorator

@handle_mq('/some/path')
def foo():
    print "foo!"

foo() # <- this code only works if I first call the decorated function

for k, v in globals().items():
    if hasattr(v, 'mq_path'):
        list_of_paths.append(v.mq_path)
        path_dispatcher[v.mq_path] = v

print list_of_paths
print path_dispatcher
path_dispatcher['/some/path']()

基本上问题是,如何在首次执行之前收集已修饰函数的列表?

我在使用Python 2.7。

1 个答案:

答案 0 :(得分:0)

我找到了答案!

list_of_paths = []
path_dispatcher = {}

def handle_mq(path):
    def decorator(fn):
        list_of_paths.append(path)
        path_dispatcher[path] = fn
        def decorated(*args,**kwargs):
            print "Hello from handl_mq decorator, your path is: {0}".format(path)
            return fn(*args,**kwargs)
        return decorated
    return decorator

@handle_mq('/some/path')
def foo():
    print "foo!"

print list_of_paths
print path_dispatcher
path_dispatcher['/some/path']()