Question

我有两个模式MONITORING和MONITORING_CONFIGURATION。我正在尝试创建一个两个模式都可以访问的表。我将脚本作为MONITORING_CONFIGURATION运行，但并不完全排除它作为MONITORING运行。我可以简单地忽略我在GRANT上获得的错误并获得权限，因为我创建了表作为MONITORING_CONFIGURATION，同时仍然实现了两个模式都可以访问的表的目标吗？错误为<Page id="tabsPage" class="page" xmlns="http://schemas.nativescript.org/tns.xsd" xmlns:t1="views/tab-test/partial-views"> tab1.xml ---------- <GridLayout columns="80,*,80" rows="100" style="background:#fff;opacity:0.95;padding:10 10;margin-bottom:20" loaded="onLoad"> <Button class="btn btn-primary" text="test button"/> <Button tap="GoToTab2" text="Go To Tab 2"/> </GridLayout>

SQL-Fehler: ORA-01749: you may not GRANT/REVOKE privileges to/from yourself
01749. 00000 -  "you may not GRANT/REVOKE privileges to/from yourself"

当我执行CREATE TABLE "MONITORING"."WEB_SERVICE_STATUS" ( "WEB_SERVICE_STATUS_ID" NUMBER, "WEB_SERVICE_ID" NUMBER, "STATUS" CHAR(1) ); GRANT ALTER, DELETE, INDEX, INSERT, SELECT, UPDATE, REFERENCES, ON COMMIT REFRESH, QUERY REWRITE, DEBUG, FLASHBACK ON "MONITORING"."WEB_SERVICE_STATUS" TO "MONITORING_CONFIGURATION";时，我看来已获得select * from "MONITORING"."WEB_SERVICE_STATUS";权限。

Answer 1

我会丢弃该表，然后将该确切脚本重新运行为MONITORING。然后你会知道你有两个用户的正确授权。

Answer 2

以下帮助 - 使用PLSQL围绕当前用户添加逻辑然后使用EXECUTE IMMEDIATE通过动态SQL采取适当的操作：

DECLARE
   vsql VARCHAR2(1000);
BEGIN
   IF user = 'MONITORING' THEN
      DBMS_OUTPUT.PUT_LINE ( ' Running as ' || USER || ' - creating table' );
      vsql := 'CREATE TABLE "MONITORING"."WEB_SERVICE_STATUS" 
   (    "WEB_SERVICE_STATUS_ID" NUMBER, 
    "WEB_SERVICE_ID" NUMBER, 
    "STATUS" CHAR(1)
   )';
      EXECUTE IMMEDIATE vsql;
      DBMS_OUTPUT.PUT_LINE ( ' Running as ' || USER || ' - issuing grant' );
      vsql := ' GRANT ALTER, DELETE, INDEX, INSERT, SELECT, UPDATE, REFERENCES, ON COMMIT REFRESH, QUERY REWRITE, DEBUG, FLASHBACK ON "MONITORING"."WEB_SERVICE_STATUS" TO "MONITORING_CONFIGURATION"';
      EXECUTE IMMEDIATE vsql;
   ELSE
      DBMS_OUTPUT.PUT_LINE ( ' Running as ' || USER || ' - no action taken' );
   END IF;
END;
/

Answer 3

您是否尝试实现schema-？

之间的连接

public partial class Form3 : Form
{
    Form2 m_form2;
    public Form3(Form2 form2)
    {
        InitializeComponent();
        m_form2 = form2;

        //here in this class you can get value of data of listview
        List<string> dataOfListView = form2.DataOfListView;
    }
}

Oracle中两个模式的权限

3 个答案: