Question

根据android developer documentation

Android 8.0（API级别26）引入了几个相关的新权限电话：ANSWER_PHONE_CALLS权限允许您的应用以编程方式接听来电。处理传入在你的应用程序中打电话，你可以使用acceptRingingCall（）方法。

我的应用如何为来电提供语音解答？

但我没有找到任何关于此的指南或示例。所以

我想用语音自动回答（来自app中的原始文件夹）（我需要指南或示例代码，如答录机）

Answer 1

https://developer.android.com/reference/android/telecom/TelecomManager.html#acceptRingingCall()

接受应答呼叫未弃用API LEVEL Q

尝试{ Toast.makeText（CallAnswerDialog.this，“ btn_answer click”，Toast.LENGTH_SHORT）.show（）;

                TelecomManager tm = (TelecomManager) CallAnswerDialog.this.getSystemService(Context.TELECOM_SERVICE);
                if (tm == null) {
                    // whether you want to handle this is up to you really
                    throw new NullPointerException("tm == null");
                }
                tm.acceptRingingCall();   // is deprecated Now API Level Q
                btn_answer.setVisibility(View.GONE);
            }catch (Exception e){
                e.printStackTrace(); }

Answer 2

要接听电话，只能在Android O上使用。以前，它可能无法工作。这是它的代码：

/**returns true iff we are sure that answering the phone call worked*/
fun answerCall(context: Context): Boolean {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
        val telecomManager = context.getSystemService(Context.TELECOM_SERVICE) as TelecomManager
        if (ContextCompat.checkSelfPermission(context, Manifest.permission.ANSWER_PHONE_CALLS) == PackageManager.PERMISSION_GRANTED
                || ContextCompat.checkSelfPermission(context, Manifest.permission.MODIFY_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
            telecomManager.acceptRingingCall()
            return true
        }
        return false
    }
    // https://stackoverflow.com/a/29651130/878126
    // for HTC devices we need to broadcast a connected headset
    val audioManager = context.getSystemService(Context.AUDIO_SERVICE) as AudioManager
    val broadcastConnected = "htc" == Build.MANUFACTURER.toLowerCase(Locale.US) && !audioManager.isWiredHeadsetOn
    if (broadcastConnected)
        broadcastHeadsetConnected(context, false)
    try {
        try {
            Runtime.getRuntime().exec("input keyevent " + Integer.toString(KeyEvent.KEYCODE_HEADSETHOOK))
        } catch (e: IOException) {
            // Runtime.exec(String) had an I/O problem, try to fall back
            val enforcedPerm = "android.permission.CALL_PRIVILEGED"
            val btnDown = Intent(Intent.ACTION_MEDIA_BUTTON).putExtra(Intent.EXTRA_KEY_EVENT, KeyEvent(KeyEvent.ACTION_DOWN, KeyEvent.KEYCODE_HEADSETHOOK))
            val btnUp = Intent(Intent.ACTION_MEDIA_BUTTON).putExtra(Intent.EXTRA_KEY_EVENT, KeyEvent(KeyEvent.ACTION_UP, KeyEvent.KEYCODE_HEADSETHOOK))
            context.sendOrderedBroadcast(btnDown, enforcedPerm)
            context.sendOrderedBroadcast(btnUp, enforcedPerm)
        }
    } finally {
        if (broadcastConnected)
            broadcastHeadsetConnected(context, false)
    }
    return false
}

为挂断电话，此功能已在Android P上正式添加，但该解决方法似乎适用于迄今为止我尝试过的大多数情况（例如，不适用于Nexus 5x和Android 8.1）。这是此代码：

@SuppressLint("PrivateApi")
fun endCall(context: Context): Boolean {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        val telecomManager = context.getSystemService(Context.TELECOM_SERVICE) as TelecomManager
        if (telecomManager != null && ContextCompat.checkSelfPermission(context, Manifest.permission.ANSWER_PHONE_CALLS) == PackageManager.PERMISSION_GRANTED) {
            telecomManager.endCall()
            return true
        }
        return false
    }
    //use unofficial API for older Android versions, as written here: https://stackoverflow.com/a/8380418/878126
    try {
        val telephonyClass = Class.forName("com.android.internal.telephony.ITelephony")
        val telephonyStubClass = telephonyClass.classes[0]
        val serviceManagerClass = Class.forName("android.os.ServiceManager")
        val serviceManagerNativeClass = Class.forName("android.os.ServiceManagerNative")
        val getService = serviceManagerClass.getMethod("getService", String::class.java)
        val tempInterfaceMethod = serviceManagerNativeClass.getMethod("asInterface", IBinder::class.java)
        val tmpBinder = Binder()
        tmpBinder.attachInterface(null, "fake")
        val serviceManagerObject = tempInterfaceMethod.invoke(null, tmpBinder)
        val retbinder = getService.invoke(serviceManagerObject, "phone") as IBinder
        val serviceMethod = telephonyStubClass.getMethod("asInterface", IBinder::class.java)
        val telephonyObject = serviceMethod.invoke(null, retbinder)
        val telephonyEndCall = telephonyClass.getMethod("endCall")
        telephonyEndCall.invoke(telephonyObject)
        return false
    } catch (e: Exception) {
        e.printStackTrace()
        return false
    }
}

因此，对于接听和拒接电话，最安全的方法是使其在Android P上运行...：（

Answer 3

在来电时，我想接收它。然后，从我的应用程序，在原始目录的通话过程中自动播放音频文件（例如“ hi，请留下message.mp3”），并且对方应听到声音。在Android O中有可能吗？如果可能的话，为什么我在您的答案中看不到声音消息的原始目录？

Answer 4

来自Google的更新：

telecomManager.acceptRingingCall();
telecomManager.acceptRingingCall(false);
telecomManager.endCall();

这三个命令在Android Q和Android Q上均已弃用

click to verify here

android.permission.ANSWER_PHONE_CALLS我怎么用？自动回答

4 个答案: